Question posted in 
How to reduce the number of visible buttons during pagination in Laravel. I have tried many methods but none of them work correctly
The $onEachSide=1 method does not work as it should
This is what the pagination looks like now
And that’s what I need
Here is the pagination code
@if ($paginator->hasPages())
<nav>
<ul class="pagination">
{{-- Previous Page Link --}}
@if ($paginator->onFirstPage())
<li class="page-item disabled" aria-disabled="true" aria-label="@lang('pagination.previous')">
<span class="page-link" aria-hidden="true">‹</span>
</li>
@else
<li class="page-item">
<a class="page-link" href="{{ $paginator->previousPageUrl() }}" rel="prev" aria-label="@lang('pagination.previous')">‹</a>
</li>
@endif
{{-- Pagination Elements --}}
@foreach ($elements as $element)
{{-- "Three Dots" Separator --}}
@if (is_string($element))
<li class="page-item disabled" aria-disabled="true"><span class="page-link">{{ $element }}</span></li>
@endif
{{-- Array Of Links --}}
@if (is_array($element))
@foreach ($element as $page => $url)
@if ($page == $paginator->currentPage())
<li class="page-item active" aria-current="page"><span class="page-link">{{ $page }}</span></li>
@else
<li class="page-item"><a class="page-link" href="{{ $url }}">{{ $page }}</a></li>
@endif
@endforeach
@endif
@endforeach
{{-- Next Page Link --}}
@if ($paginator->hasMorePages())
<li class="page-item">
<a class="page-link" href="{{ $paginator->nextPageUrl() }}" rel="next" aria-label="@lang('pagination.next')">›</a>
</li>
@else
<li class="page-item disabled" aria-disabled="true" aria-label="@lang('pagination.next')">
<span class="page-link" aria-hidden="true">›</span>
</li>
@endif
</ul>
</nav>
@endif
2
Answers
This is the only way I achieved what I wanted. It is not perfect, but it will cope with its task perfectly
Here’s my pagination function I wrote from scratch to achieve this compact mode. You may adapt the logic into your template format. I provide it as-is hope it helps.
Here are some HTML outputs