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Javascript – Regular expression – exclude all paths which contains locale and test before extension

I want exclude paths which contains ‘locale’ and ‘test’ before extension. Paths can contain dots.

branch.name/packages/components/filename.js – true

branch.name/packages/components/filename.locale.js – fail

branch.name/packages/components/filename.test.js – fail

branch.name/packages/components/filename.utils.js – true

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2

Answers


  1. 0

    You may call test() using the regex pattern:

    b(?:test|locale).w+$

    This matches test or locale followed by any extension at the end of the file.

    var files = ["branch.name/packages/components/filename.js",
             "branch.name/packages/components/filename.locale.js",
             "branch.name/packages/components/filename.test.js",
             "branch.name/packages/components/filename.utils.js"];
for (var i=0; i < files.length; ++i) {
    if (!/b(?:test|locale).w+$/.test(files[i])) {
        console.log("PASS => " + files[i]);
    }
    else {
        console.log("FAIL => " + files[i]);
    }
}
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  2. 0

    If you require at least one word character after a period to qualify as an extension, ^(?!.*(?:locale|test).w) will work.

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