Ios swift - Create JSON from given data in Swift

Vader20FF
March 16, 2024
130 views
0 votes
2 Answers

I want to execute POST URLRequest but first I need to create request body.
The body should look like this:

{
  "model": "gpt-4-vision-preview",
  "messages": [
    {
      "role": "user",
      "content": [
        {
          "type": "text",
          "text": <mutableStringValue>
        },
        {
          "type": "image_url",
          "image_url": {
            "url": <mutableStringValue>
          }
        }
      ]
    }
  ],
  "max_tokens": 300
}

I cannot hardcore this as .json file because parameters "text" (under first "type") and "image_url" (under second "type") are given as function parameters.
I don’t know how to handle two "type" keys.

As of now, I came up with something like this:

struct ImageInputRequestBody: Codable {
        let model: String = "gpt-4-vision-preview"
        let messages: [Message]
        let maxTokens: Int = 300
        enum CodingKeys: String, CodingKey {
            case model, messages
            case maxTokens = "max_tokens"
        }
        
        struct Message: Codable {
            let role: String
            let content: [Content]
        }
        struct Content: Codable {
            let type: String
            let text: String?
        }
    }

But here I’m missing second "type" and "image_url" content

Answers

You could try something simple like this:

struct Content: Identifiable, Codable {
    let id = UUID()
    let type: String
    var text: String?
    var imageUrl: ImgUrl?
    
    enum CodingKeys: String, CodingKey {
        case type, text
        case imageUrl = "image_url"
    }

    // where value is the text or the url string
    // depending on the type given (which could be an enum)
    init(type: String, value: String? = nil) {
        self.type = type
        self.text = nil
        self.imageUrl = nil
    
        if type == "text" {
            self.text = value
        } else {
            if value != nil {
                self.imageUrl = ImgUrl(url: value!)
            }
        }
    }
    
    public func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode(type, forKey: .type)
        if type == "text" {
            try container.encode(text, forKey: .text)
        } else {
            try container.encode(imageUrl, forKey: .imageUrl)
        }
    }
}

struct ImageInputRequestBody: Codable {
    let model: String = "gpt-4-vision-preview"
    let messages: [Message]
    let maxTokens: Int = 300
    
    enum CodingKeys: String, CodingKey {
        case model, messages
        case maxTokens = "max_tokens"
    }
}

struct Message: Codable {
    let role: String
    let content: [Content]
}

struct ImgUrl: Codable {
    let url: String
}

Note, you need to add two Content to the Message object.

For example:

func getTestRequestBody(text: String? = nil, url: String? = nil) -> ImageInputRequestBody {
    return ImageInputRequestBody(messages: [
        Message(role: "user", content: [
            Content(type: "text", value: text),
            Content(type: "image_url", value: url)
        ])
    ])
}

As far as I remember, if your task is to only create the json mentioned in the question, you can simply make a multiline string, and then decode it into Data.

let value1 = "your text"
let value2 = "your url"
let text = """
    {
      "model": "gpt-4-vision-preview",
      "messages": [
        {
          "role": "user",
          "content": [
            {
              "type": "text",
              "text": "(value1)"
            },
            {
              "type": "image_url",
              "image_url": {
                "url": "(value2)"
              }
            }
          ]
        }
      ],
      "max_tokens": 300
    }
    """
let encoded = text.data(using: .utf8)!

Or it can be a #"" string, to make the code more compact.

If such JSONs may have a random number of items in "content", I would make an enum with 2 cases for text and image, and implement Encodable‘s method to convert them properly. For instance

enum Content: Encodable {
    case text(String)
    case imageURL(URL)
    
    private enum CodingKeys: String, CodingKey {
        case type
        case text
        case imageURL = "image_url"
    }
    
    private enum ImageURLCodingKeys: CodingKey {
        case url
    }
    
    func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)
        switch self {
        case .text(let text):
            try container.encode("text", forKey: .type)
            try container.encode(text, forKey: .text)
        case .imageURL(let url):
            try container.encode("image_url", forKey: .type)
            var nestedContainer = container.nestedContainer(keyedBy: ImageURLCodingKeys.self, forKey: .imageURL)
            try nestedContainer.encode(url.absoluteString, forKey: .url)
        }
    }
}

I also wanted to offer a more objective way, but for some reason Apple has made encode(_:) a generic method, and to do the following code, you would need to use another JSON parser:

struct TextContent: Encodable {
    let text: String
    
    private enum CodingKeys: String, CodingKey {
        case type
        case text
    }
    
    func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode("text", forKey: .type)
        try container.encode(text, forKey: .text)
    }
}

struct ImageURLContent: Encodable {
    let url: URL
    
    private enum CodingKeys: String, CodingKey {
        case type
        case imageURL = "image_url"
    }
    
    private enum ImageURLCodingKeys: CodingKey {
        case url
    }
    
    func encode(to encoder: Encoder) throws {
        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encode("image_url", forKey: .type)
        var payloadContainer = container.nestedContainer(keyedBy: ImageURLCodingKeys.self, forKey: .imageURL)
        try payloadContainer.encode(url.absoluteString, forKey: .url)
    }
}

let content: [Encodable] = [
    TextContent(text: "your text"),
    ImageURLContent(url: URL(string: "https://test.com")!)
]
let data = SomeThirdPartyEncoder().encode(content) // JSONEncoder doesn't work with such the array, unfortunately

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Ios swift – Create JSON from given data in Swift

Answers