Question 400063 in Javascript Question posted in
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Javascript – How can I extract all desired values from string with regex groups?

I have a string:

const str = `abcde 9'2" abcde 8' abcde 7' 11" abcde`

I’m trying to extract these values:

[ "9'2", "8'", "7' 11" ]

I want to use regex groups to achieve this (my actual code is far more complex and regex groups will simplify things) but my regex is not quite working. How can I make all 3 tests return true in the code snippet below?

const str = `abcde 9'2" abcde 8' abcde 7' 11" abcde`

const regex = /(d+' ?d+)"/g

const matches = [...str.matchAll(regex)]

const actual = matches.map(x => x[1])

const expected = [ "9'2", "8'", "7' 11" ]

console.log(actual) // [ "9'2", "7' 11" ]

// tests
console.log(actual[0] === expected[0]) // true
console.log(actual[1] === expected[1]) // false
console.log(actual[2] === expected[2]) // false
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2

Answers


  1. Chosen as BEST ANSWER
    0

    With help from @user24714692 I've found a few more variations that work too!

    const str = `abcde 9'2" abcde 8' abcde 7' 11" abcde`

const regexes = [
  /[0-9]+'(?:s*[0-9]+")?/g,
  /d+'(?: *d+")?/g,
  /d+'(?: ?d+")?/g
]

for (let regex of regexes) {
  const matches = [...str.matchAll(regex)]

  const actual = matches.map(x => x[0])
  const expected = [ `9'2"`, `8'`, `7' 11"` ]

  console.log(actual)
  
  // tests
  console.log(actual[0] === expected[0]) // true
  console.log(actual[1] === expected[1]) // true
  console.log(actual[2] === expected[2]) // true
}


  2. 0

    You can use this pattern:

    [0-9]+'(?:s*[0-9]+")?

    const str = `abcde 9'2" abcde 8' abcde 7' 11" abcde`;

const regex = /[0-9]+'(?:s*[0-9]+")?/g;

const matches = [...str.matchAll(regex)];

const actual = matches.map((x) => x[0]);
const expected = [`9'2"`, `8'`, `7' 11"`];

console.log(actual[0] === expected[0]); 
console.log(actual[1] === expected[1]); 
console.log(actual[2] === expected[2]);
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