I have a simple unit-test using Catch 2.11.1:
#define CATCH_CONFIG_MAIN
#include "catch.hpp"
#include <utility>
#include <any>
namespace A::B
{
namespace C
{
struct S
{
};
}
using type = std::pair<C::S, std::any>;
}
inline bool operator==(A::B::type const&, A::B::type const&)
{
return true;
}
TEST_CASE("test", "[test]")
{
auto t1 = std::make_pair(A::B::C::S(), std::any());
auto t2 = std::make_pair(A::B::C::S(), std::any());
REQUIRE(t1 == t2);
}
The above simple programs generates the following errors:
$ g++ -Wall -Wextra -Wpedantic test-single.cpp -std=c++17
In file included from /usr/include/c++/9/bits/stl_algobase.h:64,
from /usr/include/c++/9/bits/char_traits.h:39,
from /usr/include/c++/9/string:40,
from catch.hpp:457,
from test-single.cpp:2:
/usr/include/c++/9/bits/stl_pair.h: In instantiation of ‘constexpr bool std::operator==(const std::pair<_T1, _T2>&, const std::pair<_T1, _T2>&) [with _T1 = A::B::C::S; _T2 = std::any]’:
catch.hpp:2289:98: required from ‘bool Catch::compareEqual(const LhsT&, const RhsT&) [with LhsT = std::pair<A::B::C::S, std::any>; RhsT = std::pair<A::B::C::S, std::any>]’
catch.hpp:2318:34: required from ‘const Catch::BinaryExpr<LhsT, const RhsT&> Catch::ExprLhs<LhsT>::operator==(const RhsT&) [with RhsT = std::pair<A::B::C::S, std::any>; LhsT = const std::pair<A::B::C::S, std::any>&]’
test-single.cpp:28:5: required from here
/usr/include/c++/9/bits/stl_pair.h:449:24: error: no match for ‘operator==’ (operand types are ‘const A::B::C::S’ and ‘const A::B::C::S’)
449 | { return __x.first == __y.first && __x.second == __y.second; }
| ~~~~~~~~~~^~~~~~~~~~~~
[And many many more messages after this…]
The crucial part of the error message is this line:
/usr/include/c++/9/bits/stl_pair.h: In instantiation of ‘constexpr bool std::operator==(const std::pair<_T1, _T2>&, const std::pair<_T1, _T2>&) [with _T1 = A::B::C::S; _T2 = std::any]’:
From the error message it’s clear that it’s the standard std::operator==
function for std::pair
that is being invoked, instead of my overloaded operator==
function.
If I don’t do the comparison inside the Catch REQUIRE
macro, then it works:
auto result = t1 == t2; // Invokes my overloaded comparison operator
REQUIRE(result);
Now is this a problem with Catch, or with my operator function?
NB: I’m building on Debian SID with a recent build of GCC 9.2
$ g++ --version
g++ (Debian 9.2.1-23) 9.2.1 20200110
Copyright (C) 2019 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
2
Answers
The magic that expands the operands in order to provide nice diagnostic output can fall over at times.
The workaround is to disable that with some brackets:
This is effectively the same workaround as you have with the variable.
The documentation mentions this problem in the context of more complex expressions. Exactly why the situation is being triggered in your case I am not certain, but notice from the stack trace how your
operator==
is not actually being invoked, but insteadCatch::BinaryExpr::operator==
andCatch::compareEqual
, which seems not to have access to (or otherwise chooses not to use) your implementation. Either way, the solution is to disable the decomposition machinery as noted above.Note that even with the parentheses suggested by Lightness, the code you show is exceptionally fragile.
I guess you are originally in ADL-only territory due to dependent name lookup inside the macro (see the last notes of https://en.cppreference.com/w/cpp/language/adl), and your code is quite clearly not ADL-viable. Adding parentheses makes the whole thing just an unqualified lookup, not ADL-only (again, a guess). The non-ADL part of unqualified lookup saves you in this case, but it will fall apart from entirely unrelated code changes.
Consider this code instead of the
TEST_CASE
, which is what using parentheses presumably boils down to:This compiles and works as expected: https://godbolt.org/z/HiuWWy
Now add a completely unrelated
operator==
between your globaloperator==
and thet1 == t2
:And you’re out for the count: https://godbolt.org/z/BUQC9Y
The
operator==
in the global namespace isn’t found because the (non-ADL part of) unqualified name lookup stops in the first enclosing scope that has anyoperator==
. Since that doesn’t find anything useful, it falls back to using the inbuiltstd::pair
comparison operator (found via ADL), which won’t work.Just put operator overloads in the namespaces of the objects they operate on. And by corollary, don’t overload operators for facilities from
std
(or other namespaces you are not allowed to touch).Adding from comments:
The standard currently also says that the namespaces of template arguments are considered, so putting the
operator==
innamespace C
would work (because the first template argument of std::pair comes from there): https://godbolt.org/z/eV8JojHowever, 1. that doesn’t mesh too well with your type alias and 2. there is some movement to make ADL less wild and I’ve seen discussion to get rid of the “consider namespaces of template parameters”. See http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2018/p0934r0.pdf:
I don’t know where this paper stands today but I would avoid relying on this kind of ADL in new code.