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How to get a photo path in PHP Laravel web service – Phpmyadmin

I want to make a web service using PHP Laravel which can store images.
I have made a table testing containing a colum named Photo. Now I need to make a controller to save the photo file.

Testing Table:

Description (string) null
Photo (binary) null

In the controller:

public function store(Request $request)
{    
    $photo = $request->input('photo');

    $data = new Testing();
    $data->Photo = $photo;

    if ( $data->save() ) {
        $res['message'] = 'Success';
        $res['value'] = $data;

        return response ( $res );
    } else {
        $res['message'] = 'Failed';

        return response ( $res );
    }
}

But when I hit it using postman, I choose binary for the body and I choose a .jpg file, it throws me an error saying that my photo file is null.

Can you tell me how to get the photo path in the right way?

Tags:

3

Answers


  1. 0

    You need to use this code to save photo

                if($request->hasFile('photo')){
                $image = $request->file('photo');
                $destination_path = public_path('/images/');
                $source = "Image".time().'.'.$image->getClientOriginalExtension();
                $image->move($destination_path, $source);
            }
            else{
                $source = 'default.jpg';
            }
            $add_new_photo = new Photo();
            $add_new_photo->photo = $source;
            $add_new_video->created_by = Auth::user()->name;
            $add_new_video->save();

    This will save the photo in the images folder. Make sure you create the folder using 777 mode.

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  2. 0

    You can do this : 

    if($request->hasFile('photo')){
  $image = $request->photo->store('your_image_folder');
  $data->Photo = basename($image);
  ...
}

    The store method will generate a unique ID to serve as the file name. If you want to name your file use

    $request->photo->storeAs('your_image_folder', 'your_filename')

    Then save $data

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  3. 0

    try this instead of choosing binary in body.
    You need to choose form-data in body.
    and need to change the type of the field to form

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