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How to show selected user input in my HTML form? – Phpmyadmin

I have a PHP form which saves user data to a MySQL database.

I want to show the user which information is held about them and display it in a form in order for them to update or edit the values.

I have a problem in getting the user’s saved data from the database in a PHP loop and show that to user in order for them to update or edit it.

Below is the piece of code:

            <?php
                $id = $_GET['id'];
                $conn = mysqli_connect('localhost', 'phpmyadmin', 'Test@2000', 'user');

                $sql1 = "SELECT * FROM usr WHERE id='$id'";
                $result = mysqli_query($conn, $sql1);
                $row = mysqli_fetch_assoc($result);
            ?>

            <fieldset><label>Birthday</label>
                <select name="birthday">
                <?php
                    for ($i = 1300; $i <= 1397; $i++) {
                        echo "<option >$i</option>";
                    }
                ?>
                </select>
                    <fieldset>
                <button name="btn" type="submit" id="contact-submit">Submit</button>
            </fieldset>
        </form>
    </div>
</body>
</html>

I want to show into the form’s Select input the birthday value that user selected originally, in order to edit or update by user.

Tags:

3

Answers


  1. 0

    The <select> children elements <option> does support a selected tag to indicate that it was the selected value, so by adding the selected tag like so <option value='1' selected> you can have that as the selected value.

    You’ll also want to probably add the $i value into your option element to ensure that the values are being submitted properly.

    Mozilla documentation:
    https://developer.mozilla.org/en-US/docs/Web/HTML/Element/select

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  2. 0

    I have edited your code in this way.

    <?php
$id = $_GET['id'];
$conn = mysqli_connect('localhost', 'phpmyadmin', 'Test@2000', 'user');

$sql1 = "SELECT * FROM usr WHERE id='$id'";
$result = mysqli_query($conn, $sql1);
$row = mysqli_fetch_assoc($result);
?>

        <fieldset><label>Birthday</label>
            <select name="birthday">
            <?php for ($i = 1300; $i <= 1397; $i++) {
                echo "<option" . (($i == $row['birthdayYear']) ? 'selected="true"' : '') . ">$i</option>";
            }
            ?>
            </select>
                <fieldset>
            <button name="btn" type="submit" id="contact-submit">Submit</button>
        </fieldset>
    </form>
</div>
</body>
</html>

    Hope this helps, thanks.

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  3. 0

    A.) WITH PDO MODULE

    It is best practice today to use prepared statements to avoid SQL injection. This is done through the PDO object.

    Set for select the autocomplete=”off” attribute, because Firefox apparently has a bug with the selected=”selected” that needs this to be set.

    See if it is the user’s birthday, we can use intval to compare.

    <?php
$id = $_GET['id'];

$host = 'localhost';
$username = 'phpmyadmin';
$password = 'Test@2000';
$db_name = 'user';

$conn = new PDO('mysql:host:=' . $host . '; dbname=' . $db_name, $username, $password);

$sql1 = "SELECT * FROM usr WHERE id = :id;";
$stmt = $conn->prepare($sql1);
$stmt->bindParam(':id', $id);
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
?>
        <fieldset><label>Birthday</label>
            <select name="birthday" autocomplete="off">
            <?php for ($i = 1300; $i <= 1397; $i++) {
                if($i === intval($row['birthdayYear'])){
                  echo "<option selected='selected'>$i</option>";
                } else {
                  echo "<option>$i</option>";
                }
            }
            ?>
            </select>
                <fieldset>
            <button name="btn" type="submit" id="contact-submit">Submit</button>
        </fieldset>
    </form>
</div>
</body>
</html>

    B.) Please at least try option A.), but if it doesn’t work:

    <?php
$id = $_GET['id'];

$conn = mysqli_connect('localhost', 'phpmyadmin', 'Test@2000', 'user');

$sql1 = "SELECT * FROM usr WHERE id='$id'";
$result = mysqli_query($conn, $sql1);
$row = mysqli_fetch_assoc($result);
?>
        <fieldset><label>Birthday</label>
            <select name="birthday" autocomplete="off">
            <?php for ($i = 1300; $i <= 1397; $i++) {
                if($i === intval($row['birthdayYear'])){
                  echo "<option selected='selected'>$i</option>";
                } else {
                  echo "<option>$i</option>";
                }
            }
            ?>
            </select>
                <fieldset>
            <button name="btn" type="submit" id="contact-submit">Submit</button>
        </fieldset>
    </form>
</div>
</body>
</html>
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