Question 173985 in Javascript Question posted in
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Javascript – Can anyone help me to turn this string into an array of numbers without losing zeros(0).And not using regExp

Can anyone help me to turn this string into an array of numbers without losing zeros(0)? And not using regExp

"00ghj67 h4 h000ytff700jhjk80" -> [0,0,67,4,0,0,0,700,80] 

function extractNumbers(string) {
    let arrNumbs = [];
    let numbers = "";
    for (let i = 0; i < string.length; i++) {
        let elem = string.charAt(i);
        if (!isNaN(elem)) {
            numbers += elem;
        } else if (numbers !== "") {
            arrNumbs.push(parseInt(numbers));
            numbers = "";
        }
    }
    if (numbers !== "") {
        arrNumbs.push(parseInt(numbers));
        return arrNumbs;
    }
    return arrNumbs;
}
extractNumbers("00ghj67 h4 h000ytff700jhjk80");
console.log(extractNumbers(string)); //->[ 0, 67, 4, 0, 700, 80 ]
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5

Answers


  1. 0

    You can add a special case for 0.

    function extractNumbers(string) {
    let arr = [], curr = "";
    function add() {
      if (curr) arr.push(+curr), curr = "";
    }
    for (const c of string) {
      if (!curr && c === '0') arr.push(0);
      else if (isNaN(c)) add();
      else curr += c;
    }
    add();
    return arr;
}
console.log(extractNumbers("00ghj67 h4 h000ytff700jhjk80"));
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  2. 0

    The problem is that parseInt(numbers) will skip the leading zeros. So you have to handle it in a special case. I have modified your code.

    function extractNumbers(string) {
  let arrNumbs = [];
  let numbers = "";
  for (let i = 0; i < string.length; i++) {
    let elem = string.charAt(i);
    // if it's zero, add it and reset numbers 
    // this will handle leading zeros
    if (numbers === "0") {
      arrNumbs.push(0);
      numbers = "";
    }
    if (!isNaN(elem)) {
      numbers += elem;
    } else if (numbers !== "") {
      arrNumbs.push(parseInt(numbers));
      numbers = "";
    }
  }
  if (numbers !== "") {
    arrNumbs.push(parseInt(numbers));
    return arrNumbs;
  }
  return arrNumbs;
}
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  3. 0

    Turn the input string into an array of individual characters using the spread operator. Then, in the accumulator array of reduce, start a new string whenever we reach a digit directly after a non-digit (and also when a string containing only zero is followed by another zero). Then, for numeric characters, append it to the most recent string in the accumulator array. Finally, use the + operator to coerce the the array of strings into an array of numbers.

    const isNum = c => c>='0' && c<='9'

console.log([...'00ghj67 h4 h000ytff700jhjk80'].reduce((a,c,i,r) => (
  (a[a.length-1]==='0' && c==='0' || isNum(c) && i && !isNum(r[i-1]))
  && a.push(''), isNum(c) && (a[a.length-1] += c), a), ['']).map(i => +i))
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  4. 0

    But if anyone is looking for regexp instead:

    function extractNumbers (str) {
    return str.match(/0|[1-9]d*/g).map(v => +v);
}
console.log(extractNumbers('00ghj67 h4 h000ytff700jhjk80'));
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  5. 0

    a shorter one:

    document.write(JSON.stringify(extractNumbers('00ghj67 h4 h000ytff700jhjk80')));

function extractNumbers(str)
  {
  let arr = [], sNum = '';
  for (const c of str + '_')
    {
    if      (c==='0' && !sNum)  arr.push(0);
    else if (!isNaN(c))         sNum += c.trimEnd();
    else if (!!sNum)
      {
      arr.push(parseInt(sNum,10));
      sNum = '';
      }
    }
  return arr;
  }
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