Question 174293 in Javascript Question posted in
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Javascript – Is it possible to have such a regex?

I have a string like this:
124:111,120:444,103:504,494:120,404:111,200:100,

I will use replace() and let’s say I want to select
124:111,120:444,103:504,494:120,404:111,**200:100,**
without actually defining 200:100, but instead having it to work like this:

Define only :100, regex selects everything to the left until "," approaches and everything to the right including first "," => 200:100,

Is it possible to have such a regex? Thanks for any information

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2

Answers


  1. 0

    Without using replace() you could do it this way in my opinion.

    1. Define the regex pattern and matches any sequence of characters that does not include a comma

      const pattern = /[^,]*:100,/;

    2. Use match() to find a match of the pattern in the input string:

      const match = string.match(pattern);

    3. Check if a match is found

      if (match) {
 const result = match[0];
  console.log(result);
} else {
  console.log("Pattern not found");
}
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  2. 0

    Regex

    ,?(d*?):100

    Will match :100 and capture the digits before that:

    const regex = /,?(d*?):100/gm;
const sourceValue = '124:111,120:444,103:504,494:120,404:111,200:100,';
const match = regex.exec(sourceValue);

console.log(match[1]);
// 200

    split()

    Another option is to split on ,, then check if the right side has the value you’re searching for

    const sourceValue = '124:111,120:444,103:504,494:120,404:111,200:100,';
const searchValue = 100;

sourceValue.split(',').forEach(p => {
    const [ l, r ] = p.split(':');
    if (+r === searchValue) {
        console.log(`Found searchValuennLefttt${l}nRighttt${r}nOriginalt${p}`);
    }
});
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