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Making a script in debian which would create a new file from names file with different order of the names

Existing names in the "names" file is in form of lastname1,firstname1 ; lastname2,firstname2.

In the new file it should be like down below.

Create a script that outputs a list of existing users (from the "names" file) in the form:

firstname1.lastname1
firstname2.lastname2
etc.

And saves a file called "cat list"

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2

Answers


  1. 0

    This kind of command line should be a solution for you :

     awk -F '.' '{print $2","$1}' source_file >> "cat list"
    • First awk revers the order of the field and put the char ‘,’ under
    • ">>" Second step redirect full output to a file called "cat list" as requested
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  2. 0

    I don’t think I have the most efficient solution here but it works and outputs the different stages of translation to help illustrate the process:

    #!/bin/sh

echo "lastname1,firstname1 ; lastname2,firstname2" >testfile
echo "original file:"
cat testfile
echo "n"

# first replace semi-colon with newline
tr ';' 'n' <testfile >testfile_n
echo "after first translation:"
cat testfile_n
echo "n"

# also remove extra spaces
tr -d '[:blank:]' <testfile_n >testfile_n_s
echo "after second translation:"
cat testfile_n_s
echo "n"

# now swap name order using sed and use periods instead of commas
sed -E 's/([a-zA-Z0-9]*),([a-zA-Z0-9]*)/2.1/g' testfile_n_s >"cat list"
echo "after third iteration:"
cat "cat list"
echo "n"

    The script above will save a file called ‘cat list’ and output something similar to:

    original file:
lastname1,firstname1 ; lastname2,firstname2


after first translation:
lastname1,firstname1
 lastname2,firstname2


after second translation:
lastname1,firstname1
lastname2,firstname2


after third iteration:
firstname1.lastname1
firstname2.lastname2
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