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PHP eliminate "if" for simple assignment

I have code that looks like this:

$foo = false;

$ar = ["bar", "baz"];

if ($foo === true)  {
    $ar[] = "corge";
}

 
var_dump($ar);

so if $foo is true, $ar should look like this: ["bar", "baz", "corge"], otherwise it should look like this: ["bar", "baz"].

Is there a shorthand operator in php that will allows me to eliminate that if?

solutions like ternary, null coalesce and Elvis all create a third element when $foo is false.

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3

Answers


  1. 0

    It’s much less clear in its intent, but it’s certainly possible to write it like this:

    $foo === false or $ar[] = "corge";

    Live demo: https://3v4l.org/5XHeb

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  2. 0

    You can use a ternary along with array_merge(). Merge with an empty array to avoid pushing anything.

    $ar = array_merge($ar, $foo ? ["corge"] : []);
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  3. 0

    To have another option you could use a ternary operator.

    $foo ? $ar[] = "corge" : null;

    If $foo is true, corge will be added, else nothing happens. Instead of null you could use any other value, because it has no effect.

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