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Php versions – How to extract Version number from the web content using preg_match php

I would like to extract the version number from the url content. i tried to extract info using curl_exec. but unable to get the preg_match to get the exact info.

Code i tried is 

function getVersionFromurl(string $url)
{
    $curl = curl_init($url);
    $content = curl_exec($curl);
    curl_close($curl);
    $rx = preg_match("("version" (d+.d+.d+.d+))", $content, $matches);
    echo $matches[1];
}

$url = 'https://www.foxitsoftware.com/downloads/downloadForm.php?retJson=1&product=Foxit-Reader&platform=Mac-OS-X';
$val = getVersionFromurl($url);

here the content came as

“{“package_info”:{“language”:[“English”,”French”,”German”,”Italian”,”Spanish”],”type”:[“pkg”],”version”:[“3.4.0.1012″,”2.1.0804″,”2.0.0625″,”1.1.1.0301″,”1.1.0.0128″],”size”:”139.13MB”,”release”:”10/15/19″,”os”:””,”down”:”/pub/foxit/reader/desktop/mac/3.x/3.4/ML/FoxitReader340.setup.pkg”,”mirror”:””,”manual”:””,”big_version”:”3.x”}}1″

How to extract 3.4.0.1012 from the content.
the preg_matcxh i tried gives me error. how to write the preg_match regular expression.

Please any help.

Tags:

2

Answers


  1. 0

    better to convert string to JSON object, and get version value from there

    function getVersionFromurl(string $url)
{
    $curl = curl_init($url);
    $content = curl_exec($curl);
    curl_close($curl);

    $contentObj = json_decode($content);
    echo $contentObj.package_info.version[0];
}

$url = 'https://www.foxitsoftware.com/downloads/downloadForm.php?retJson=1&product=Foxit-Reader&platform=Mac-OS-X';
$val = getVersionFromurl($url);

    Notice this conversion from string into object, and get first element of version array

    $contentObj = json_decode($content);
echo $contentObj.package_info.version[0];
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  2. 0

    In your pattern you are not accounting for this part :[" after "version"
    You are also using 2 capturing groups, so $matches[1] would then contain the whole match and $matches[2] would contain your value.

    But instead, you can use 1 capturing group.

    "version":["(d+(?:.d+){3})"

    Regex demo | Php demo

    preg_match('~"version":["(d+(?:.d+){3})"~', $content, $matches);
echo $matches[1];

    Output

    3.4.0.1012

    Note that you don’t have to escape the double quotes and that you have to use delimiters for the pattern.

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