Why is printing argc & argv’s content weird?
this is the code and it runs as intended. #include <stdio.h> int main( int argc, char* argv[]) { printf (" this is the contents of argc:%dn",argc); int i; for (i = 0; i < argc ; i++){ printf(" argv =…
this is the code and it runs as intended. #include <stdio.h> int main( int argc, char* argv[]) { printf (" this is the contents of argc:%dn",argc); int i; for (i = 0; i < argc ; i++){ printf(" argv =…