Perl :: Translate String "yyyy.mm.dd.hh.mm.ss" into DateTime object? – Ubuntu
newbie Perl guy here. I have a Perl script (v5.26.1) that parses a logfile. For reasons beyond my control, the format of each date in the log is this: "yyyy.mm.dd.hh.mm.ss" e.g.: "2022.09.19.16.35.00" Note that year is always four digits, while…