Now, I have retrieved the element data. But, I don't know how to get data of data-properties enter image description here I tried: $('#checkout_shipping_address_id').on('select2:select', function (e) { var data = e.params.data; console.log(data.element.getAttribute[data-properties]); }); but It's not working
I need to display SQL query results by having specified columns appear first (on the leftmost side of the table). The currrent code I have is: Select * from table order by column 4, column 3, column 1 Result: column…
Been googling and looking for an answer to this / best practice. Let's say you have most of your javascript inside $(document).ready() for whatever reason, and inside there you have a function that you want to "fire" based on some…
Hi im doing an App with Datatables and i have a problem when i want to try to edit a record in the datatables this is my js function in app.blade.php $(document).on('click', '.editButton', function(e) { e.preventDefault(); var id = $(this).data("id");…
I created a Grid using jsGrid library. the code is pasted below. On click of the image, the user should navigate to another page function fillpatientsGrid(){ $("#patientsgrid").jsGrid({ width: "90%", height: "600px" , sorting: true, paging: true, pageSize: 12, data: patientsData,…
Here is the code I wrote, and I tried to modify it but couldn't find the right solution for my problem <!-- Main content --> <main> <p> Click the menu button in the top right corner to see the menu…
I am using the dynamic method where the name and id of input the element will be in different languages but I am facing this issue. Like if the input id of the element is a mixture of English and…
I want to make a WooCommerce Checkout Field that only shows up when a specific payment (Cash On Delivery) is chosen. This field should only show up and only be required when cash on delivery is chosen. I have managed…
let z = document.getElementById('id_z') let x = document.getElementById('id_x') let y = document.getElementById('id_y') $("#id_a, #id_b, #id_c, #id_d, #id_e").keyup(function () { let a = $('#id_a').val() let b = $('#id_b').val() let c = $('#id_c').val() let d = $('#id_d').val() let e = $('#id_e').val() z.value…
From within the succcess method of my AJAX response, my goal is to do the following in an XSS safe manner: remove all existing options within a select box. replace the options from that same select box. Here is one…