SQL: update a row if *condition* on another row – Php versions
I have a problem in SQL. I want to update a value on a given row if and only if a value on another row matches a condition; then update another value on the second row. Ok it can't be…
I have a problem in SQL. I want to update a value on a given row if and only if a value on another row matches a condition; then update another value on the second row. Ok it can't be…
I'm having difficulty to make a cron job on cpanel to update the state of an user if the account has been created for 5 days. It just doesn't work at all. When I program the cron job on the…
I am trying to make a java program program can takes just one row/line from phpMyAdmin database. what I mean is in the photo The problem is that I couldnt figure out how to take just the first line because…
I have a Problem getting UTF-8 encoded Strings out of a MariaDB-Database. Today I updated my XAMPP-Distro to 10.4.11-MariaDB (MySql) and PHP 7.2.29 and now a strange Problem arised wich had not occoured with the older version. Preliminary informations: I…
I have some problem with jquery. Why there is a problem accessing a variable in the json string? $(function() { var jqxhr = $.ajax({ type: "POST", url: "test.php", async: false, cache: false, timeout: 10000, data: { test: "test" }, success:…
Receiving the following error message: Error Static analysis: 1 errors were found during analysis. This option conflicts with "AUTO_INCREMENT". (near "AUTO_INCREMENT" at position 692) SQL query: -- phpMyAdmin SQL Dump -- version 2.8.2.4 -- http://www.phpmyadmin.net -- -- Host: localhost:3306 --…
I have a join query which takes a lot of time to process. SELECT COUNT(c.id) FROM `customers` AS `c` LEFT JOIN `setting` AS `ssh` ON `c`.`shop_id` = `ssh`.`id` LEFT JOIN `customer_extra` AS `cx` ON `c`.`id` = `cx`.`customer_id` LEFT JOIN `customers_address`…
Table: id | name 1 | a,b,c 2 | b Output id | name 1 | a 1 | b 1 | c 2 | b I found this query online and it works fine in mySql Phpmyadmin query editor.…
on my website i'm using a form to ulpoad the images of the users that compiles that form. Then, that image should be automatically displayed through a simple query and php, and it just worked fine until i've discovered that…
I wanted to execute the following statement to create a table for storing various details .Here name of movies will store there "Ratings in integer value" Please help me solve this issue CREATE TABLE users ( id INT NOT NULL…