function foo(num) { return new Promise((resolve) => console.log(num)); } foo(1).then(() => { foo(3); }); The function foo returns an immediately resolve promise. "1" is printed, but why doesn't the chain continue with printing "3"?
Promice is rewriting value of hook, i tried to get more values to my posts, but promise keep replacing value of hook with value of data const loadNewProducts = async() =>{ while(posts.length<15){ await fetch (`http{loadLimit[0]}&limit=${loadLimit[1]}&sort=title%3Aasc`) .then((res) => res.json()) .then((data) =>…
I have a React component with 3 buttons representing 3 choices the user can make. If the user clicks a button and then another button I cancel the previous HTTP request using AbortController.signal.abort(), it is really incredibly simple. The thing…
I had been struggling with the doubt , since in the event loop job queue has more priority than callback queue i.e, promises have more priority than setTimeout, then what about : new Promise(resolve => setTimeout(resolve, 0, "Done!")).then((message) => console.log(message));…
Consider the following code, which awaits a Promise: async function handleSubmit() { try { await submitForm(answer); } catch (err) { console.log('Error') } } function submitForm(answer) { return new Promise((resolve, reject) => { setTimeout(() => { if (answer !== 'OK') {…
I am working with the promises and async function. The thing I got to know that inside the async function if there is a await out JS engine will suspend the ongoing call stack's function calls and wait for the…
Consider this: const a = () => { return new Promise((resolve) => { resolve(1); }); }; const b = () => { return new Promise((resolve) => { a() .then((aR) => { console.log(aR); resolve(2); }) .finally(() => { console.log("A"); }); });…
I've learned javascript async/await before learning promise.then() syntax, and I am now attempting to go back and learn promise.then(). I currently have the following code let getDatabaseData = async () => { let res1 = await dbQuery() let res2 =…
[Promise.reject(42), Promise.resolve(4)].forEach((item, i) => { Promise.resolve(item) .then(() => console.log("resolve", i)) .catch(() => console.log("reject", i)); }); Expected output: reject 0 resolve 1 Actual output: resolve 1 reject 0
For all of the convert to base 64 functions I have found on stack overflow it requires using a promise. So i create a function that generates a new promise and I await on it for the response then return…