How to extract the password from this string in bash: "–db_host db –db_password $£é5+dd/gcç# –db_name zorgl"? – Debian
I have tried this on Debian, but it fails: echo "--db_host db --db_password $£é5+dd/gcç# --db_name zorgl" | sed -e "s/^.*db_password *([^ ]+) +.*$/1/" Result (no match): --db_host db --db_password $£é5+dd/gcç# --db_name zorgl Expected result: $£é5+dd/gcç#