This is so simple query. I need to update Bookings tables', LinkedBookings column (int array data type) to it's own Id. Below query didn't work for me. update public."Booking" b set "LinkedBookings" = {"Id"} Above is giving below error, SQL…
How to select values in sql with null result For example we have next table user code user1 code 1 user3 code 2 user4 code 4 Select select * from table where user in ( 'user1', 'user2', 'user3', 'user4') Result…
I have SQL table such as this: TABLE1 STUDENT SCORE SCOREVAL 1 PASS 10 1 MOD1 4 1 MOD2 5 2 MOD1 4 3 MOD2 2 3 MOD2 1 3 MOD1 9 3 ER 1 4 MOD2 10 4 ER…
This is my query: SELECT a.Id, a.Title, (SELECT m.Id, m.Name, m.MobileNo FROM [msm].[MsmMember] AS m WHERE m.Id = a.MemberId AND m.OrganizationId = @OrganizationId FOR JSON PATH, WITHOUT_ARRAY_WRAPPER) AS Member FROM msm.MsmArticleSubmission a WHERE a.OrganizationId = @OrganizationId AND a.Id = @Id…
I have 3 queries that I need to see in the same query editor window but can't seem to figure out how Postgres wants it. I have a background in T-SQL where it's intuitive enough to run this and return…
I have a table of stock ID Qty DatePurchased Price 11202 4 01/01/2023 3 11202 3 12/06/2023 7 5050 4 11/10/2023 60 11202 4 12/10/2023 5 5050 8 12/12/2023 70 and Item sold table ID Qty 11202 6 I want…
I am learning Snowflake right now, and the way FLATTEN() works is a bit counter intuitive. A simple query. SELECT raw:first_name::STRING AS FName, raw:last_name::STRING AS LName, f.value::STRING AS Skill FROM tbl, TABLE(FLATTEN(raw:Skills)) f ORDER BY raw:id::INT LIMIT 5; Elegantly, it…
I have a database table for a telephone billing system. Rates are matched by the longest prefix found, so that more specific rates can be used for certain numbers. Let's say the table looks like this: Column Type id SERIAL…
My business requirement is to store lists of issues & responses as JSON data within a SQL Server 2019 table. Each list corresponds to a page within a document. At minimum, I'd like to be able to retrieve the GUID…
I have this string in some MariaDB Column (let's called it MY_COL): {"libelle": "comu00e9dien"} that i'd like to replace it with {"libelle": "acteur"} Using this STO post, I figured out how to select rows containing this string: SELECT MY_COL FROM…