Button for Updating a Database single entry with PHP AJAX Call – Jquery ajax

For Future Readers, this was my first question and the answer has been found (read comments and replies below):

First of all, i’ve searched in Stackoverflow and i didn’t found an answer for a similar problem.

i would like to link a html Button (among many buttons) with a JQuery function. The function shall execute AJAX method like so :

HTML Code in a separated file index.php:

<button id="submitbtn" type="button" class="btn btn-success">UPDATE</button>

JQuery Function :

    $('#submitbtn').on('click', function(){
        var id = $(this).data('id');

        $.ajax({
            url: 'includes/updatequery.php',
            type: 'POST',
            data: {id:id},
            success: function(data){
                if (data) {
                console.log("updated");
                } else {
                    $('#error').load("custom/static/error.html");
                }
            },
            error: function(jqXHR, textStatus, errorThrown){
                $('#error').html("oops" + errorThrown);
            }
        });
    });    

Here is the PHP file that should be called by AJAX Method :

<?php
include("src/db.php");
$query = "UPDATE mytable SET job='completed' WHERE id=id";
mysqli_query($conn, $query);
  
?>

The problem is that i CANNOT link the ID of the clicked button (because there are many buttons) to the ID of the Database Entry in order to update the Data in the Database according to this specific button.

Now i would like to have the results updated LIVE after updating the Database.

This is the PHP code that output menu items (items stored in the same Database table as before) and in front of every menu item, a badge should be displayed (with a value within it : "completed" or "not completed") :

<?php 
            foreach($data as $d) {
              $id = $d['id'];
              $mystatus = $d['status'];
            ?>
              <li class="nav-item">
                <a class="nav-link clickable blueMenuItem" id="nav-location" data-id="<?php echo $d['id']; ?>">
                  <i class="nav-icon fas <?php echo $d['icon']; ?>"></i>
                  <p><?php
                    echo $d["title"];
                    if ($d['type'] == "job") { ?>
                      <span id="updatedicon" class="right badge <?php if($mystatus == "completed"){echo "badge-success";} else {echo "badge-danger";}?>"><?php setJob($con, $id)?></span><?php
                    } ?>
                  </p>
                </a>
              </li><?php
            }
          ?>

Here is the PHP file where the setJob method is defined :

<?php

function setJob($con, $idd) {

$sql = "SELECT status FROM mytable WHERE id=$id";
$result = mysqli_query($con, $sql); 
while ($row = mysqli_fetch_assoc($result)) { 
    foreach ($row as $row => $value) { 
        echo $value; 
   }
}
} 
?>

Any suggestions?

Thanks