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execute a function after previous function is complete – Jquery ajax

How to call a function after the previous function is complete? In the code below the second_function() is executed before the first_function() and the data get suffled

first_function();
second_function();

function name() {
  if (condition == true) {
    let tdbody = document.createElement('td');
    tdbody.classList.add("class1");
    let tdbodytext = document.createTextNode(userincourseres[i].fullname);
    tdbody.appendChild(tdbodytext);
    trbody.appendChild(tdbody);
  }
}


async function first_function() {
  await name();
  if (condition == true) {
    var tdbody = document.createElement('td');
    var tdbodytext = document.createTextNode(get_grade_res.grade);
    tdbody.classList.add("class2");
    tdbody.appendChild(tdbodytext);
    trbody.appendChild(tdbody);
  }
}

function second_function() {
  if (condition == true) {
    var tdbody = document.createElement('td');
    var tdbodytext = document.createTextNode(get_grade_res.grade);
    tdbody.classList.add("class3");
    tdbody.appendChild(tdbodytext);
    trbody.appendChild(tdbody);
  }
Tags:

2

Answers


  1. 0

    The behaviour is expected, please have a look of the below example.

    first_function();
second_function();

function name() {
  console.log("name");
}

async function first_function() {
  await name();
  console.log("first");
}

function second_function() {
  console.log("second");
}

    It can be written as

    function name() {
  console.log("name");
}

function second_function() {
  console.log("second");
}

Promise.resolve(name()).then(() => {
  console.log("first");
});

second_function();
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  2. 0

    Either do it like this

    first_function().then(() => first_function())

    Or if you want to use the asyncawait syntax

    async function callingFunc() {
   await first_function();
   second_function();
}
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