Getting SQL error while submitting form via ajax - Jquery ajax

user2852960
June 4, 2020
127 views
0 votes
2 Answers

I have a simple form with one input field and one submit button. When i click submit, i get error

This is the query in php. Query:

   //Using MySQLi
    $stmt = $con->prepare("INSERT INTO `emailsubscribe` 
    (email,medium,country)VAlUE(?,?,?)"); // Use prepared statements. 
    $stmt-> bind_param("sss", $email, $medium, $country);
    $stmt-> execute();

This table has 3 columns email, medium and country.

    $('#formoid').on('submit', function() {
       $.ajax({
            type: "POST",
            url: "subscribe.php",
            data: $(this).serialize(),
	success: function(data){
            $('.message').html(data).fadeIn();
            }
        });
    return false;
});

<div class="message" style="color:black;"></div>
      <form action="subscribe.php" title="" method="post" id="formoid">
        <input type="email" id="email" name="email" minlength="7" size="40" placeholder="Enter your email here.." required><br><br>
        <input type="hidden" name="medium" value="subbox" />
        <input type="hidden" name="country" value="<?php echo $country; ?>" />
        <input type="submit">	 
      </form>

Answers

First, let’s wrap up the HTML data.

<div class="message"></div>
<form action="subscribe.php" name="subscribeForm">
    <input type="email" name="emailsub" minlength="7" size="40" placeholder="Enter your email here.."><br><br>
    <select name="medium">
        <option value="">Select Medium</option>
        <option value="english">English</option>
        <option value="hindi">Hindi</option>
        <option value="japanese">Japanese</option>
    </select>
    <br><br>
    <select name="country">
        <option value="">Select Country</option>
        <option value="India">India</option>
        <option value="USA">USA</option>
        <option value="Japan">Japan</option>
    </select><br><br>
    <input type="submit" id="action"> 
</form>

AJAX code below takes the form details and sends to subscribe.php. Note that document.subscribeForm below takes your form field variables and stores in the form. For this only name value in HTML part is enough. Hence, I have not added any id field in the HTML form fields.

$('#action').click(function() { 
    var form = document.subscribeForm;
    var dataString = $(form).serialize();
    $.ajax({
      type: 'POST',
      url: $(form).attr("action"),
      data: dataString,
      beforeSend: function(){
        $('.message').hide();
        $("#action").val('Please wait...');
      },
      success: function(data){
        $('.message').html(data).fadeIn();
      }
    });
    return false;
});

Once the data is sent to subscribe.php, it’s now time to process it.

// Storing data in variables
$email = (!empty($_POST['emailsub'])?$_POST['emailsub']:null;
$medium = (!empty($_POST['medium'])?$_POST['medium']:null;
$country = (!empty($_POST['country'])?$_POST['country']:null;

if($_POST){
    // Check if email submitted is empty or not. If yes, script will stop executing further.
    if($email == null){
        echo "Email is required";
        exit();
    }

    // Check if medium submitted is empty or not. If yes, script will stop executing further.
    if($medium == null){
        echo "Medium is required";
        exit();
    }

    // Check if country submitted is empty or not. If yes, script will stop executing further.
    if($country == null){
        echo "Country is required";
        exit();
    }

    // All checks cleared. Process the data.

    //Using MySQLi
    $stmt = $con->prepare("INSERT INTO emailsubscribe(email, medium, country)VAlUES(?,?,?)"); // Use prepared statements. 
    $stmt-> bind_param($email, $medium, $country);
    $stmt-> execute();

    // Using PDO (Better: A big bonus is that you can use a readable `:name` instead of confusing `?`)
    $stmt = $con->prepare("INSERT INTO emailsubscribe(email, medium, country)VAlUES(:email, :medium, :country)"); // Use prepared statements. 
    $stmt-> bindValue(':email', $email);
    $stmt-> bindValue(':medium', $medium);
    $stmt-> bindValue(':country', $country);
    $stmt-> execute();

    // Echo Message
    if($stmt){
        echo "Success";
    }else{
        echo "Error";
    }
}

This is the proper way how you should process your forms.

Firstly I don’t see any medium or country in your form as inputs. So I changed your HTML code

$('#formoid').on('submit', function() {

  $.ajax({
    type: "POST",
    url: "subscribe.php",
    data: $(this).serialize(),
    success: function(response) {
      $(this).hide(); //sets css display:none to form
      var message = "Thank you!";
      $('.container-fluid').html(message);
    }
  });

});

<form action="subscribe.php" title="" method="post" id="formoid">
  <input type="email" id="emailsub" name="email" minlength="7" size="40" placeholder="Enter your email here.." required><br><br>
  <input type="text" id="" name="medium" size="40" placeholder="Enter here.." required>
  <input type="text" id="" name="country" size="40" placeholder="Enter here.." required>
  <input type="submit">

</form>

Then in your subscribe.php do the following. Take note, I just copied your exact SQL code. Use prepared statements or PDO to avoid SQL injection

$qry = mysqli_query($con,"INSERT into `emailsubscribe` (email,medium,country) value ('".$_POST['email']."','".$_POST['medium']."','".$_POST['country']."')");

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Getting SQL error while submitting form via ajax – Jquery ajax

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