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How do I combine my ajax request into one line? – Jquery ajax

I am successfully looping my data with ajax but when I console log I see my data sent in a new line.

$.ajax(settings).done(function(response) {
  $.get(settings).then(data => makeTable(data.contracts))
  const makeTable = (contracts) => {
      const body = document.getElementById('chart');
      contracts.forEach((person, index) => {
        person.details.forEach((entry) => {
          const arrayOfDigits = Array.from(String(entry.hours), Number);
          chart.updateSeries([{
            name: 'Hours',
            data: [entry.hours]
          }])

          console.log(arrayOfDigits)

I also tried converting my integers into an object but it would come out as

[integer]
[integer]
[integer]
[integer]
[integer]

But what I would like to do is having it in the same object like so

[integer, integer, integer, integer]
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2

Answers


  1. 0

    Push arrayOfDigits into an array and log that at the end, rather than logging each one separately.

    const makeTable = (contracts) => {
  const body = document.getElementById('chart');
  const result = [];
  contracts.forEach((person, index) => {
    person.details.forEach((entry) => {
      const arrayOfDigits = Array.from(String(entry.hours), Number);
      chart.updateSeries([{
        name: 'Hours',
        data: [entry.hours]
      }])
      result.push(arrayOfDigits);
    });
  });
  console.log(result);
}
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  2. 0

    Final code working as intended:

    $.ajax(settings).done(function (response) {
    $.get(settings).then(data => makeTable(data.contracts))
    const makeTable = (contracts) => {
        const body = document.getElementById('chart');
        const result = [];
        contracts.forEach((person, index) => {
            person.details.forEach((entry) => {
                result.push(entry.hours);
            });  
        }); 
    chart.updateSeries([{
            name: 'Hours',
            data: [result]
      }])
        console.log(result);
    }
});
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