Question posted in
You can find the official documentation here.

How to return promise from "ajax success"? – Jquery ajax

I need to write function which prepare me a HTML to inuput into my site, I tried like this

function prepareHTML(valId){
  $.ajax({
    type: "POST",
    url: "SOAPulr_getData",
    data: {operationId: valId}
  })
  .done(function(result, status, jqXHR){
    var def = $.Deferred();
    var response = jqXHR.responseText;
    var outputHTML;
    [... here i generate HTML code ...]
    def.resolve(outputHTML);
    return def.promise();
  });
}

now when i tried to run this function:

prepareHTML(22)
.done(function(data){
  console.log(data)
});

I get an error:
TypeError: prepareHTML(…) is undefined
when I run prepareHTML(22) there is no error in console.

What I do wrong?

—

Best regards

ssnake

Tags:

2

Answers


  1. Chosen as BEST ANSWER
    0

    Yes I can do this like that:

    function prepareHTML(valId){
  res = $.ajax({
    type: "POST",
    url: "SOAPulr_getData",
    data: {operationId: valId}
  });

  return res.promise();
}

    and it works but then I must to generate my HTML into done function:

    prepareHTML(22).done(function(result, status, jqXHR){
    var response = jqXHR.responseText;
    [... here i generate HTML code ...]
});

    Question is: is it possible to pre-process the respone to have HTML ready in the done function

    I need something like this:

    prepareHTML(22).done(function(myHTML){
    // here I need ready HTML code prepared into prepareHTML() function
    $("#myId").html(myHTML);
});

  2. 0

    prepareHTML has no return statement so it returns undefined

    return $.ajax...
    Login or Signup to reply.
Please signup or login to give your own answer.

Back To Top
Search