Question 69564 in Ajax Question posted in
You can find the official documentation here.

How to use same php function for different button clicks – Jquery ajax

Here is a simple PHP form with a button..

<form method="POST">
  <div class="mb-3">
       <button  type='button'  id ="btnnew1" class="btn btn-info" >submit</button>
       <p></p>
  </div>
</form>

Here is the Jquery functions which executes a PHP file.

$(document).ready(function(){
    $("#btnnew1").click(function(e){
        if(!confirm('Are you sure?')){
            e.preventDefault();
            return false;
        }
        else{
          $.ajax({
            url: 'test.php',
            success: function(data) {
                $("p").text(data);
             }
          });
          
        }
    });
});

And the test.php is as follows,

<?php

echo 'Button1 clicked' 
?>

My question is how to modify my test.php if I have multiple buttons.

As an example,

<form method="POST">
      <div class="mb-3">
           <button  type='button'  id ="btnnew1" class="btn btn-info" >submit</button>
           <p></p>
      </div>
<div class="mb-3">
           <button  type='button'  id ="btnnew2" class="btn btn-info" >submit</button>
           <p></p>
      </div>
<div class="mb-3">
           <button  type='button'  id ="btnnew3" class="btn btn-info" >submit</button>
           <p></p>
      </div>
    </form>

Result should be,

If btnnew1 clicks--->echo("Button1 clicked);
If btnnew2 clicks--->echo("Button2 clicked);
If btnnew3 clicks--->echo("Button3 clicked);

Update:

What If I need to run three different php functions(no any pattern)?

Ex:
    If btnnew1 clicks--->
     sleep(5)
     echo("Button1 clicked);

If btnnew2 clicks--->
     sleep(15)
     echo("Button2 clicked by user);
If btnnew3 clicks--->
     sleep(35)
     echo("Button3 clicked by user);
Tags:

2

Answers


  1. 0

    Set the name to each button:
    Button 1

    Send data using ajax:
    Get button text using e.target.text and send using POST method.

    $.ajax({
  type: 'POST',
  url: 'test.php',
  data: { buttonTitle: e.target.name},
  success: function(data) {
      $("p").text(data);
    }
});

    php:
    Inside php use $_GET to get the data which we send from the frontend.

    if(isset($_POST['buttonTitle'])) {    
  $buttonTitle = $_POST['buttonTitle'];
  echo $buttonTitle . " clicked";
}
    Login or Signup to reply.
  2. 0

    In here I am changing little bit your default settings. This will help you as I can understand. You can try as below,

    1)Change your button into input type..I have added some inline CSS as well. If you don’t like you may neglect it…

    <input type="button" style="background-color: #3CBC8D;padding:3px;"   class="button" name="fcn1" value="Update My Status"/>


<input type="button" class="button" style="background-color: #3CBC8D;padding:3px;" name="fcn2" value="Update My Status" />

    1. Then go to jquery and use as below, success function change as you wish. Here I have used an alert box…

         $(document).ready(function(){
       $('.button').click(function(){

         if(!confirm('Are you sure?')){
             e.preventDefault();
             return false;
         }
         else{
         var clickBtnValue = $(this).attr('name');
         var fetchdata= 'testme.php',
         data =  {'action': clickBtnValue};
         $.post(fetchdata, data, function (response) {
             // Response div goes here.

             alert("Updated successfully -"+response);

         });
         }

     });

 });

    2. Finally change your testme.php as follows,

       if (isset($_POST['action'])) {
     switch ($_POST['action']) {
         case 'fcn1':
             fcn1();
             break;
         case 'fcn2':
             fcn2();
             break;
     }
 }

 function fcn1() {

     echo 'Button1 clicked';
     exit;
 }

 function fcn2() {
     sleep(5);
     echo 'Button2 clicked';
     exit;
 }
    Login or Signup to reply.
Please signup or login to give your own answer.

Back To Top
Search