Question 126541 in Android Studio Question posted in
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Android Studio – problem with setVisibility when swithching between two ImageView elements in Java

    imageView1.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view)
        {
            if(imageViewGet1.getDrawable() != null){
                imageView1.setVisibility(View.INVISIBLE);
                imageViewGet1.setVisibility(View.VISIBLE);
            }
            OpenGallery1();

        }
    });
    imageView2.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view)
        {
            if(imageViewGet2.getDrawable() != null){
                imageView2.setVisibility(View.INVISIBLE);
                imageViewGet2.setVisibility(View.VISIBLE);
            }
            OpenGallery2();

        }
    });

when I run the code and open galley to pick new photo, after that, the imageView with the old one still appear
how I can fix that so when I choose new image, the imageView1 disappear and imageViewGet appear with the new Image.

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2

Answers


  1. Chosen as BEST ANSWER
    0

    I tried this :

    imageView1.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view)
            {
                OpenGallery1();

                    imageView1.setVisibility(View.INVISIBLE);
                    imageViewGet1.setVisibility(View.VISIBLE);
                if(imageViewGet1.getDrawable()==null){
                    imageView1.setVisibility(View.VISIBLE);
                }
            }
        });

    and it works fine.


  2. 0

    try to use

    imageView1.setVisibility(View.GONE);

    if are views overlapping (one is in front of second).

    .setVisibility(View.INVISIBLE);

    just makes view invisible, but doesn’t hide it.

    If this won’t help, you may can use Shared Preferences to store bool with image (in)visibility state.

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