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How to get all external links found on a page using BeautifulSoup? – Artificial Intelligence

I’m reading the book, Web Scraping with Python which has the following function to retrieve external links found on a page: 

#Retrieves a list of all external links found on a page
def getExternalLinks(bs, excludeUrl):
    externalLinks = []
    #Finds all links that start with "http" that do
    #not contain the current URL
    for link in bs.find_all('a', {'href' : re.compile('^(http|www)((?!'+excludeUrl+').)*$')}):
        if link.attrs['href'] is not None:
            if link.attrs['href'] not in externalLinks:
                externalLinks.append(link.attrs['href'])
    return externalLinks

The problem is that it does not work the way it should. When i run it using the URL: http://www.oreilly.com, it returns this: 

bs = makeSoup('https://www.oreilly.com') # Makes a BeautifulSoup Object
getExternalLinks(bs, 'https://www.oreilly.com')

Output:

['https://www.oreilly.com',
 'https://oreilly.com/sign-in.html',
 'https://oreilly.com/online-learning/try-now.html',
 'https://oreilly.com/online-learning/index.html',
 'https://oreilly.com/online-learning/individuals.html',
 'https://oreilly.com/online-learning/teams.html',
 'https://oreilly.com/online-learning/enterprise.html',
 'https://oreilly.com/online-learning/government.html',
 'https://oreilly.com/online-learning/academic.html',
 'https://oreilly.com/online-learning/pricing.html',
 'https://www.oreilly.com/partner/reseller-program.html',
 'https://oreilly.com/conferences/',
 'https://oreilly.com/ideas/',
 'https://oreilly.com/about/approach.html',
 'https://www.oreilly.com/conferences/',
 'https://conferences.oreilly.com/velocity/vl-ny',
 'https://conferences.oreilly.com/artificial-intelligence/ai-eu',
 'https://www.safaribooksonline.com/public/free-trial/',
 'https://www.safaribooksonline.com/team-setup/',
 'https://www.oreilly.com/online-learning/enterprise.html',
 'https://www.oreilly.com/about/approach.html',
 'https://conferences.oreilly.com/software-architecture/sa-eu',
 'https://conferences.oreilly.com/velocity/vl-eu',
 'https://conferences.oreilly.com/software-architecture/sa-ny',
 'https://conferences.oreilly.com/strata/strata-ca',
 'http://shop.oreilly.com/category/customer-service.do',
 'https://twitter.com/oreillymedia',
 'https://www.facebook.com/OReilly/',
 'https://www.linkedin.com/company/oreilly-media',
 'https://www.youtube.com/user/OreillyMedia',
 'https://www.oreilly.com/emails/newsletters/',
 'https://itunes.apple.com/us/app/safari-to-go/id881697395',
 'https://play.google.com/store/apps/details?id=com.safariflow.queue']

Question:

Why are the first 16-17 entries considered “external links”? They belong to the same domain of http://www.oreilly.com.

Tags:

2

Answers


  1. 0

    there is a difference between these two:

    http://www.oreilly.com
https://www.oreilly.com

    hope you got my point.

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  2. 0 
    import urllib
from bs4 import BeautifulSoup
from urllib.request import urlopen
from urllib.parse import urlsplit
import re
ext = set()
def getExt(url):
    o = urllib.parse.urlsplit(url)
    html = urlopen(url)
    bs = BeautifulSoup(html, 'html.parser')
    for link in bs.find_all('a', href = re.compile('^((https://)|(http://))')):
        if 'href' in link.attrs:
            if o.netloc in (link.attrs['href']):
                continue
            else:
                ext.add(link.attrs['href'])
getExt('https://oreilly.com/')
for i in ext:
    print(i)
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