Asp.net - Divide XML into specific nodes

Dima
December 1, 2023
162 views
3 votes
3 Answers

There is an XML string. I can’t figure out how to get only the contents of the node, and then split it into separate Persons.

<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:soap="http://">
    <soap:Body>
        <GetJob xmlns="http:// ">
            <GetResult>
                <Result>00</Result>
                <Data>
                    <Person>
                        <Name>Ивано Иван Иванович</Name>
                        <Active>true</Active>
                    </Person>
                    <Person>
                        <Name>Петров Петр Петрович</Name>
                        <Active>true</Active>
                    </Person>
                </Data>
            </GetResult>
        </<GetJob >
    </soap:Body>
</soap:Envelope>

I tried something like

  XElement contacts = XElement.Parse();
contacts.Element(Element("GetJob ").Element("GetResult")

            XElement contacts = XElement.Parse(
                @"<?xml version=""1.0"" encoding=""utf-8""?>
<soap:Envelope xmlns:soap=""http://"">
    <soap:Body>
        <GetJob xmlns=""http:// "">
            <GetResult>
                <Result>00</Result>
                <Data>
                    <Person>
                        <Name>Ивано Иван Иванович</Name>
                        <Active>true</Active>
                    </Person>
                    <Person>
                        <Name>Петров Петр Петрович</Name>
                        <Active>true</Active>
                    </Person>
                </Data>
            </GetResult>
        </<GetJob >
    </soap:Body>
</soap:Envelope>");
            IEnumerable<XElement> de =
      from el in contacts.Descendants("soap")
      select el;
            foreach (XElement el in de)
                Console.WriteLine(el);

            XElement contacts = XElement.Parse(
                @"<?xml version=""1.0"" encoding=""utf-8""?>
<soap:Envelope xmlns:soap=""http://"">
    <soap:Body>
        <GetJob xmlns=""http:// "">
            <GetResult>
                <Result>00</Result>
                <Data>
                    <Person>
                        <Name>Ивано Иван Иванович</Name>
                        <Active>true</Active>
                    </Person>
                    <Person>
                        <Name>Петров Петр Петрович</Name>
                        <Active>true</Active>
                    </Person>
                </Data>
            </GetResult>
        </<GetJob >
    </soap:Body>
</soap:Envelope>");
            IEnumerable<XElement> de =
      from el in contacts.Descendants("soap")
      select el;
            foreach (XElement el in de)
                Console.WriteLine(el);

Returns an error:"Name cannot begin with the ‘<‘ character, hexadecimal value 0x3C. Line 18, position 11." I tried it using the method of the Doctoral Candidates

Tags: .net asp.net c#xml

Answers

This code will work for you.

var xml = new XmlDocument();
xml.LoadXml(xmlString);
var node = xml.GetElementsByTagName("GetResult")[0];

var ls = new List<Person>();
foreach (XmlNode n in node["Data"].GetElementsByTagName("Person"))
{
    ls.Add(new Person
    {
       Name =n["Name"].InnerXml,
       Active = n["Active"].InnerXml == "true" ? true : false
    });
}

You can try this code

    XDocument doc = XDocument.Parse(xml);

    var personDetails = doc.Descendants()
    .Where(x => x.Name.LocalName == "Person")
    .Select(x => new
    {
         Name = x.Elements().Where(i=> i.Name.LocalName == "Name").First().Value,
         Active = x.Elements().Where(i=> i.Name.LocalName == "Active").First().Value
    }).ToList();

or if you have only 2 Person properties

var personDetail = doc.Descendants()
    .Where(x => x.Name.LocalName == "Person")
    .Select(x => new
    {
         Name = x.Elements().First().Value,
         Active = x.Elements().Last().Value 
    }).ToList();

Please try the following solution based on LINQ to XML API. It is available in the .Net Framework since 2007.

All XML elements starting from <GetJob xmlns='http://wow2'>, and down below, are bound to the default namespace. So, we need to declare that namespace and use it in the expressions.

void Main()
{
    XDocument xdoc = XDocument.Parse(@"<soap:Envelope xmlns:soap='http://wow'>
            <soap:Body>
                <GetJob xmlns='http://wow2'>
                    <GetResult>
                        <Result>00</Result>
                        <Data>
                            <Person>
                                <Name>Ивано Иван Иванович</Name>
                                <Active>true</Active>
                            </Person>
                            <Person>
                                <Name>Петров Петр Петрович</Name>
                                <Active>true</Active>
                            </Person>
                        </Data>
                    </GetResult>
                </GetJob>
            </soap:Body>
        </soap:Envelope>");

    XNamespace ns2 = "http://wow2";

    var persons = xdoc.Descendants(ns2 + "Person")
        .Select(x => new
        {
            Name = x.Element(ns2  + "Name").Value,
            Active = x.Element(ns2 + "Active").Value
        }).ToList();
    
    Console.WriteLine(persons);
}

Output

Name	Active
Ивано Иван Иванович	true
Петров Петр Петрович	true

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Asp.net – Divide XML into specific nodes

Answers