My code is :
#!/bin/bash
strversion=`apache2ctl -v | awk '{print $3}' | sed 's/(Debian)//g;s/Server//g;s/built//g;s/2022-06-09T04:26:43//g'`
echo ${strversion%}
exit 0
i get this:
Apache/2.4.54
but i will have to look
Apache version 2.4.54
My code is :
#!/bin/bash
strversion=`apache2ctl -v | awk '{print $3}' | sed 's/(Debian)//g;s/Server//g;s/built//g;s/2022-06-09T04:26:43//g'`
echo ${strversion%}
exit 0
i get this:
Apache/2.4.54
but i will have to look
Apache version 2.4.54
2
Answers
Try the following:
strversion=$(apache2ctl -v | head -1 | awk -F '[ /]' '{printf "%s version %s", $3, $4}')That’s because the variable expansion is not quoted. An unquoted variable is subject to Word Splitting (and Filename Expansion)
See also Security implications of forgetting to quote a variable in bash/POSIX shells