Question 46453 in Debian Question posted in
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How to extract the password from this string in bash: "–db_host db –db_password $£é5+dd/gcç# –db_name zorgl"? – Debian

I have tried this on Debian, but it fails:

echo "--db_host db --db_password $£é5+dd/gcç# --db_name zorgl" | sed -e "s/^.*db_password *([^ ]+) +.*$/1/"

Result (no match):

--db_host db --db_password $£é5+dd/gcç# --db_name zorgl

Expected result:

$£é5+dd/gcç#
Tags:

2

Answers


  1. 0

    Using sed

    $ sed -E 's/.*db_password ([^ ]*).*/1/' input_file
$£é5+dd/gcç#
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  2. 0

    Post by HatLess will fail if password contains space. This should do:

    sed -E 's/.*db_password (.*?) --db_name.*/1/' file
$£é5+d d/gcç#
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