Question 47009 in Debian Question posted in
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jq not writing value of variable but the actual text of the variable name – Debian

I’m scripting in bash to edit a json template to replace some field values with arguments to my script, and trying to use jq to do the editing. My code is not replacing the –arg with the value of the argument, but the literal text of the argument name.

My template contains:

{
"name":""
}

My jq code:

jq --arg ad "192.168.5.5" -r '.name = "Addr $ad"' address.tmpl

This outputs:

{
    "name": "Addr $ad"
}

Or, if I remove the double-quotes

jq --arg ad "192.168.5.5" -r '.name = Addr $ad' address.tmpl

I get

jq: error: syntax error, unexpected '$', expecting $end (Unix shell quoting issues?) at <top-level>, line 1:
.name = Addr $ad
jq: 1 compile error

According to all that I have read, this should work. What am I doing wrong/how do I fix this????

OS = debian 10

Tags:

2

Answers


  1. 0 
    jq --arg ad 192.168.5.5 -r '.name = "Addr " + $ad' address.tmpl

    $ad will be expanded by the shell if it is not not hard quoted. In jq, you can use string interpolation "Addr ($ad)", or concatenation (as above), which I find slightly more readable.

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  2. 0

    In the jq manual, search for "String interpolation"

    jq --arg ad "192.168.5.5" -r '.name = "Addr ($ad)"'
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