Question 88757 in Docker Question posted in
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Run image of local dockerfile with a name on a docker-compose

I’m a beginner in docker / docker-compose and i’m trying to run a container from a local docker file

my dockerFolder look like this

├── docker-compose.yml
└── dockerfiles
    ├── dockerfile.test1
    └── dockerfile.test2

What did i should put on the docker-compose file ?

I try it but it doesn’t work

version: "3.9"
services:
  test1:
    build: dockerfiles/dockerfile.test1
  test2:
    build: dockerfiles/dockerfile.test2

(I had warned that I’m a beginner)

Tags:

2

Answers


  1. 0

    You can use context and dockerfile to specify a custom Dockerfile name like you are doing:

    version: "3.9"
services:
  test1:
    build:
      context: dockerfiles
      dockerfile: dockerfile.test1
  test2:
    build:
      context: dockerfiles
      dockerfile: dockerfile.test2

    You can also keep the build but naming your files Dockerfile and put them of two distinct directories.

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  2. 0

    docker-compose does not recognize your context, the build argument requires the context (the folder where your Dockerfile is located).
    to build from dockerfiles named differently, you must first specify the context and then the name of your dockerfile
    as in the following example

    version: "3.9"
services:
  test1:
    build:
      context: ./dockerfiles
      dockerfile: dockerfile.test1

  test2:
    build: 
    context: ./dockerfiles
    dockerfile: dockerfile.test1

    where dockerfile is a subdirectory of parent directory wich contain the docker-compose file

    check the docker-compose file reference for more details https://docs.docker.com/compose/compose-file/build/

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