Question 119883 in Firebase Question posted in
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firebase auth keeps throwing an PLatformException on Vscode even I handle exceptions with try – catch

I’m going through a weird behavior using the signInWithEmailAndPassword method of firebase_auth

the try catch block should catch if an error is thrown but a PLatformException flows up in the editor like I did call a normal async/await method without catching errors :

the weird thing is that I already used the same code in a previous project and it’s working fine, I did the same configuration, and it’s working fine with correct auth data, just if there is an error it doesn’t catch it
my code :

  Future handleLoginProcess(BuildContext context) async {

_handleInputsCases();
_startLoading();
try {
  await FirebaseAuth.instance.signInWithEmailAndPassword(
      email: "[email protected]", password: "SuperSecretPassword!");
} on FirebaseAuthException catch (e) {
  print('Failed with error code: ${e.code}');
  print(e.message);
}
_endLoading();

}

the thrown error seem to direct me to this:

if (errorCode is String && (errorMessage == null || errorMessage is String) && !buffer.hasRemaining) {
  throw PlatformException(code: errorCode, message: errorMessage as String?, details: errorDetails, stacktrace: errorStacktrace);
} else {
  throw const FormatException('Invalid envelope');
}

I’m missing something, what are the possible reasons to this, is it something related to vscode?

please share your ideas with me, thanks

Tags:

3

Answers


  1. 0

    If this code working well in your another project. then you should check SDK Version of both projects. You can find SDK version in YAML file.

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  2. 0

    Check your flutter implementation too.

    In pubspec.yaml

    firebase_auth: ^3.11.2

    Code

        Future loginWithUserEmail({@required String email, @required String password}) async{
    try{
      var userCredential = await _firebaseAuth.signInWithEmailAndPassword(
          email: email,
          password: password
      );
      //await _populateCurrentUser(userCredential.user);
      return userCredential.user != null;
    }catch(error){
      return error.toString();
    }
  }
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  3. 0

    When i went through this error the only solution i found was to create a whole new project on Firebase, on Google console and on my computer.

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