Question 118915 in Firebase Question posted in
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List all files and folders in a specific subdirectory from Firebase Cloud Storage through Python

I would like to list all the files and folders in a specific directory inside firebase cloud storage. I have tried using files = storage.list_files() from other stack overflow answers. This lists all the files and folders. I have tried using files = storage.list_files(prefix='images/') but it does not work.

I am using pyrebase4 to initialize the app and I have even provided serviceAccount but it did not work.

bucket = storage.bucket()
bucket.list_blobs(prefix="files/")

Please respond with the libraries you are importing, the syntax of initializing firebase app and finally the code to fetch list of all files from a specific directory in firebase cloud storage.

If the above is not possible, would it be very resource demanding (time & cost) to do a storage.list_files().includes(file_to_be_searched) every time? for let’s say, 10k total files.

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2

Answers


  1. Chosen as BEST ANSWER
    0

    For posterity, the list_files() will always list all the files because it is deprecated. https://github.com/thisbejim/Pyrebase/issues/414#issuecomment-1100009426

    This code should work to list all the files and folders in a specific directory (copying from the link mentioned above).

    $ pip install pyrebase
$ pip install pyrebase4

import pyrebase

firebase = pyrebase.initialize_app(config)
storage = firebase.storage()

path = "images/"
files = storage.bucket.list_blobs(prefix=path)

# print file names
for file in files:
    print(file.name)

  2. 0

    The example provided is using the firebase admin sdk for python.

    Given that you said you are using pyrebase you’d have to use pyrebase

    import pyrebase

# configure firebase app
config = {
  "apiKey": "apiKey",
  "authDomain": "projectId.firebaseapp.com",
  "databaseURL": "https://projectId.firebaseio.com",
  "storageBucket": "projectId.appspot.com",
# DO NOT FORGET SERVICE ACCOUNT
"serviceAccount":"path to service account"
}

firebase = pyrebase.initialize_app(config)
storage = firebase.storage()

# specify directory path
directory_path = "path/to/directory"

# list files in directory
files = storage.list_files(directory_path)

# print file names
for file in files:
    print(file.name)

    would it be very resource demanding (time & cost)

    Yes it will to both.

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