Question 178403 in Flutter Question posted in
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Flutter – Dart: Error parsing JSON with nested json embedded in string

I am having issue with the below code, the following code failed to parse the given json:

import 'dart:convert';

void main() {
  String jsonString = '''
    {
      "status": "success",
      "data":{
        "edit": 1,
        "draft": "{"id":"25863","type":"ABC"}"
      }
    }
  ''';

    try{
    var decode = jsonDecode(jsonString);
    print(decode);
  }on FormatException catch(e){
    print('error ${e.toString()}');
  }
}

The error I am getting:

error FormatException: Unexpected character (at line 6, character 31)

Also I have used jsonDecode(jsonEncode(jsonString)), but that’s does not meet my requirements as I require the data as Map<String, dynamic>. Any help is highly appreciated.

Tags:

3

Answers


  1. 0

    You have a too much at the draft line at the end. Also you need to escape the with another if you want to use backslashes in a string definition.

      String jsonString = '''
    {
      "status": "success",
      "data":{
        "edit": 1,
        "draft": "{\"id\":\"25863\",\"type\":\"ABC\"}"
      }
    }
  ''';

    But it is kind of strange that you let the "draft" field be another JSON string. It would make more sense as this and I think you should use this:

      String jsonString = '''
    {
      "status": "success",
      "data":{
        "edit": 1,
        "draft": {
          "id": "25863",
          "type": "ABC"
        }
      }
    }
  ''';
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  2. 0

    we have to change this to "draft": "{"id":"25863","type":"ABC"}" this "draft": {"id":"25863","type":"ABC"} by removing this " between json will do it. but you have to make sure your api response will be same formate

    import 'dart:convert';

void main() {
  var jsonString = '''{
      "status": "success",
      "data": {
        "edit": 1,
        "draft": "{"id":"25863","type":"ABC"}"
      }
    }''';
  String purifiedJsonString = jsonString.replaceAll(r'"{', '{').replaceAll(r'}"', '}');


  print(purifiedJsonString);
  var result=  jsonDecode(purifiedJsonString);
  print(result);
  print(result['data']['draft']);
}
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  3. 0

    You can use like this:

    import 'dart:convert';
void main() {
String jsonString = '
  {
  "status": "success",
  "data":{
    "edit": 1,
    "draft": "{"id":"25863","type":"ABC"}"
  }
}
';
 Data jsonData = Data.fromJson(jsonDecode(jsonString));
 print(jsonData);
 print(jsonData['data']['draft']);

    }

    It is better to follow architecture. So, don’t forget to create model and then use this code. Create model of the Data class first after then pass the json converted String to the model. with the use of model you can easily get an error message if you use wrong dataType other by default it will convert int to String as well.

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