skip to Main Content
class AmtException implements Exception {
  String errMsg() => 'Amount should not be less than zero';
}

void main() {
  try {
    var amt = -1;
    if (amt < 0) {
      throw AmtException();
    }
  } catch (e) {
    print(e.errMsg());
  }
}

I am trying to create custom exception and throw the object of custom exception class. But when I am trying to call the method of custom class exception.

Error

dart/exceptions.dart:81:11: Error: The method ‘errMsg’ isn’t defined for the class ‘Object’.

  • ‘Object’ is from ‘dart:core’.
    Try correcting the name to the name of an existing method, or defining a method named ‘errMsg’.
    error.errMsg();

2

Answers


  1. When you use catch (e), it means you’re catching any errors, so the type for e is Object.

    If you want to catch a specific error, use the on NameOfTheException catch (e) syntax:

    try {
      throw AmtException();
    } on AmtException catch (e) {
      // Now `e` is an `AmtException`
      print(e.errMsg());
    }
    
    Login or Signup to reply.
  2. The catch block in your code basically catches all unexpected exceptions that may occur in your code. And that’s exactly why the e has the type Object instead of AmtException.

    Solution 1

    You can specifically catch the AmtException as follows.

      try {
        // your code
      } on AmtException catch (e) {
        print(e.errMsg());
      }
    

    Solution 2

    You can catch all exception as in your code, and double check if the e is an instance of the AmtException to continue with the errMsg() call. You can use the following code for this behaviour:

      try {
        // your code
      } catch (e) {
        if (e is AmtException) {
          print(e.errMsg());
        }
    
        // Handle other exceptions (if needed)
        // ...
      }
    
    Login or Signup to reply.
Please signup or login to give your own answer.
Back To Top
Search