Question 79904 in Flutter Question posted in
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Given an array of strings, return another array containing all of its longest strings. using Dart – Flutter

Given an array of strings, return another array containing all of its longest strings.

Example

For inputArray = ["aba", "aa", "ad", "vcd", "aba"], the output should be
solution(inputArray) = ["aba", "vcd", "aba"].

[execution time limit] 4 seconds (dart)

[input] array.string inputArray

[input] array.string inputArray

A non-empty array.

Guaranteed constraints:
1 ≤ inputArray.length ≤ 10,
1 ≤ inputArray[i].length ≤ 10.

[output] array.string

[output] array.string

Array of the longest strings, stored in the same order as in the inputArray.

I know that the javascript code answer of the above question but did’t know how to write it into dart.
this is the javascript //

  var maxLength = Math.max(...inputArray.map(s => s.length));
    return inputArray.filter(s => s.length === maxLength);
Tags:

2

Answers


  1. 0

    You can sort the list by its item’s length and then search for items that have equal length to the longest item in sorted list. like this:

    var inputArray = ["aba", "aa", "ad", "vcd", "aba"];
inputArray.sort(
  (a, b) => b.length.compareTo(a.length),
);
var result = inputArray
    .where((element) => element.length == inputArray.first.length)
    .toList();
print("inputArray = $result"); //[aba, vcd, aba]

    or use reduce instead of sort, like this:

    var maxString = inputArray.reduce(
    (value, element) => element.length > value.length ? element : value);

var result = inputArray
    .where((element) => element.length == maxString.length)
    .toList();
print("inputArray = $result"); //[aba, vcd, aba]
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  2. 0

    This is pretty easy.

    final inputArray = ["aba", "aa", "ad", "vcd", "aba"];

final lenArr = inputArray.map((e) => e.length).toList()..sort();
final finalArr = inputArray.where((el) => el.length == lenArr.last);

log(finalArr.toString()); // [aba, vcd, aba]

    Output:

    [aba, vcd, aba]
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