I am learning Flutter and currently am trying to send the index of the list item that is clicked, to another page. I have figured out how to open the new page using GestureDetector but am getting an error when trying to send the index as a string. Here is my code:
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: Text(widget.title),
),
body: ListView.builder(
itemCount: totalItems,
itemBuilder: (context, index) {
return GestureDetector(
child: Container( // This is the back container which will show next cell colour on the rounded edge
color: index == totalItems-1
? Colors.transparent
: colours[(index+1)%2],
child: Container(
height: 180,
decoration: BoxDecoration(
borderRadius:
const BorderRadius.only(bottomLeft: Radius.circular(85.0)),
color: colours[index%2],
),
child: Center(
child: Text(
index.toString(),
style: const TextStyle(color: Colors.white, fontSize: 50),
),
),
),
),
onTap: () => Navigator.push(
context,
MaterialPageRoute(
builder: (context) => const Portfolio(title: 'Portfolio', index: toString(index)),
)
);
},
)
When trying to send index to the next page as "toString(index)", I am getting an error that states
"A value of type Null can’t be assigned to a parameter of type String
in a const constructor"
When hardcoding a string, the code works. I just don’t understand how index is a type Null here.
Thank you!
2
Answers
I see you’re trying to convert the
index
to String and then open it the new screen if so the:replace:
with:
If portfolio page accepts index as:-
String
: pass index asindex.toString()
int
: pass index asindex
or you have to remove the
const
before pushing the page.modified code: