Question 78352 in Flutter Question posted in
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How to compare existing list with list from user? using dart and flutter

I want the user input to compare with each list (normalList, protanList,deutanList, tritanList)

so, assuming if the the user input is 1 – 15 correctly, and the output will be "Normal"

if the user input is [15,14,1,2,13,12,3,4,11,10,5,6,9,8,7] ,the output will be "Protan"

Please help, this is my final year project and I’m totally blank about what to do

late List<Box> opaqueBoxes = []; //to be filled

//assume opaqueBoxes being input by user here

//the result method is to compare the outcome of the result
String result() {
String result = ”;
if (listEquals(normalList, opaqueBoxes)) {
result = "Normal";
} else {
result = "Protan";
}
if (kDebugMode) {
print(result);
}
return result;
}

//here is the list of the correct one

var normalList = [
"1",
"2",
"3",
"4",
"5",
"5",
"6",
"7",
"8",
"9",
"10",
"11",
"12",
"13",
"14",
"15"
];
var protanList = [
"15",
"14",
"1",
"2",
"13",
"12",
"3",
"4",
"11",
"10",
"5",
"6",
"9",
"8",
"7"
];

var deutanList = [
"1",
"15",
"2",
"3",
"14",
"13",
"4",
"12",
"5",
"6",
"11",
"10",
"7",
"9",
"8"
];

var tritanList = [
"1",
"2",
"3",
"4",
"5",
"6",
"7",
"15",
"8",
"14",
"9",
"13",
"10",
"11",
"12"
];

Tags:

2

Answers


  1. 0

    So I already documented what I wanted to say in the code below. But here is a quick one.

    First, note that I don’t think listEquals is in support anymore. You will have to create your filter condition.

    This is easy and complex. There is no way to get a variable name without typing
    them or writing a new class. Well, deep in and see what I did. I will try and make things easy and strong.

    Also when posting a question with the codebase, always use the "Code Sample not the "Blockquote" on your textarea.

    If you need further assistance let me know.

    // First, note that I don't think `listEquals` is in support anymore. You will have
// create your filter condition.
// This is easy and complex. There is no way to get a variable name without
// typing them or writing a new class writing a new function. Well, deep in 
// and see what I did. I will try and make Things easy and strong.

void main() {
  //   I changed to type `Box` to `String` as we are getting a string input
  late List<String> opaqueBoxes = [
    "1",
    "15",
    "2",
    "3",
    "14",
    "13",
    "4",
    "12",
    "5",
    "6",
    "11",
    "10",
    "7",
    "9",
    "8"
  ];

  // Lists to filter against. Added type casting
  final List<String> normalList = [
    "1",
    "2",
    "3",
    "4",
    "5",
    "5",
    "6",
    "7",
    "8",
    "9",
    "10",
    "11",
    "12",
    "13",
    "14",
    "15"
  ];
  final List<String> protanList = [
    "15",
    "14",
    "1",
    "2",
    "13",
    "12",
    "3",
    "4",
    "11",
    "10",
    "5",
    "6",
    "9",
    "8",
    "7"
  ];
  final List<String> deutanList = [
    "1",
    "15",
    "2",
    "3",
    "14",
    "13",
    "4",
    "12",
    "5",
    "6",
    "11",
    "10",
    "7",
    "9",
    "8"
  ];
  final List<String> tritanList = [
    "1",
    "2",
    "3",
    "4",
    "5",
    "6",
    "7",
    "15",
    "8",
    "14",
    "9",
    "13",
    "10",
    "11",
    "12"
  ];

  // transform your list-based filter to list of objects based for easy filtering
  final List allFilterList = [
    {"name": "normal", "list": normalList},
    {"name": "protan", "list": protanList},
    {"name": "deutan", "list": deutanList},
    {"name": "tritan", "list": tritanList},
  ];

  // result output
  String result = "No such list!";

  for (Map list in allFilterList) {
    // filter using `any` Function from dart `List` class
    bool filter = opaqueBoxes.any((item) => list["list"].contains(item));
    if (filter) result = list["name"];
  }

  print("result: $result"); // result: tritan
}
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  2. 0

    #TO PUT EVERYTHING SIMPLY

    If you need both lists to maintain the same sequence, then try this way :

    bool isSame = a.every((item) => item == b[a.indexOf(item)]);
//List `a` is getting compared with list `b`.

    And if you don’t need to have the items in exact same sequence you can try this :

    bool isSame = a.every((item) => b.contains(item));
//List `a` is getting compared with list `b`.

    Now you can try and figure out your ways to create a result from it. And learn in the process. Good luck. 👍

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