Question 248872 in Flutter Question posted in
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How to detect emulator or real device in flutter?

I want to detect the difference between an emulator and a real device. I use the device_info_plus package to determine whether the device is an emulator or a real device. It works well, but when I try to run my app and test it in Bluestacks, NoxPlayer, or LDPlayer, it doesn’t work. When I run it in those emulators, the result is that it detects the device as a real device. How can I solve this problem?

I am trying to run my app on emulators such as Bluestacks, NoxPlayer, and LDPlayer to test whether it is running on an emulator or a real device. However, the emulators are being detected as real devices. How can I fix this?

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2

Answers


  1. Chosen as BEST ANSWER
    0

    I have found a solution to the problem:

    • Add the get_radio_version_plugin: ^0.0.1-beta* plugin to your pubspec.yaml file.

    • Get the value of radioVersion and compare it to the following values:

      • 1.0.0.0
      • "" (empty string)
      • null

    • If radioVersion is equal to any of these values, then the device is an emulator. Otherwise, the device is a real device.

    Example Code :

    if(radioVersion == '1.0.0.0' || radioVersion == ''|| radioVersion == null){
  //Emulator
} else {
  //Real Device
}

    >> Image Result <<


  2. 0

    Try this:

    class HomeScreen extends StatefulWidget {
  const HomeScreen({super.key});

  @override
  State<HomeScreen> createState() => _HomeScreenState();
}

class _HomeScreenState extends State<HomeScreen> {
  @override
  Widget build(BuildContext context) {
    return Scaffold(
      body: SafeArea(
        child: ElevatedButton(
          onPressed: () async {
            log("isPhysicalDevice: ${await checkIsPhysicalDevice()}");
          },
          child: const Text("Check Is Physical Device"),
        ),
      ),
    );
  }

  Future<bool> checkIsPhysicalDevice() async {
    final AndroidDeviceInfo androidInfo = await DeviceInfoPlugin().androidInfo;
    final bool finalCondition = androidInfo.fingerprint.startsWith("generic") ||
        androidInfo.fingerprint.startsWith("unknown") ||
        androidInfo.model.contains("google_sdk") ||
        androidInfo.model.contains("Emulator") ||
        androidInfo.model.contains("Android SDK built for x86") ||
        androidInfo.manufacturer.contains("Genymotion") ||
        androidInfo.brand.startsWith("generic") ||
        androidInfo.device.startsWith("generic") ||
        androidInfo.product == "vbox86p" ||
        androidInfo.device == "vbox86" ||
        androidInfo.hardware == "vbox86" ||
        androidInfo.product == "google_sdk";
    return Future<bool>.value(finalCondition);
  }
}

    I assure you that it is more accurate than androidInfo.isPhysicalDevice.

    OR

    Try this: safe_device

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