Question 76746 in Flutter Question posted in
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How to take attribute name list of an object in Flutter?

I’m a newbie Flutter programmer.
Im trying to make a generic grid widget that let me pass an object and create columns and rows dynamically.

I’ve made it work with an specific object but what i need is to read the names of attributes of an object to dynamically create grid column names and values so i can use the same grid for client or articles or everything.

For example i have a class for clients

class Client {
  int id;
  String name;
  String mail;

  Client({required this.id, required this.name, required this.mail});
}

then in my code retrieve a list of clients and pass that to the grid widget as List.

I just need to know how to loop the object recieved to:

  1. get the list of fields names (id, name, mail)
  2. then get its value for example something like
    var field_name = element; 
    obj.field_name.value;

Hope you can understand what im trying to do.
Thank you in advance.

Tags:

2

Answers


  1. 0

    you can try this code

    FutureBuilder<List<Client>>(
            future: // your future method which return the List<Client>,
            builder: (context, snapshot) {
              if (snapshot.hasData) {
                return ListView.builder(
                  itemCount: snapshot.data!.length,
                  itemBuilder: (context, index) {
                    final client= snapshot.data![index];
                    return ListTile(
                      title: Text(client.name),
                      leading: CircleAvatar(
                        child: Text(client.id),
                      ),
                      subtitle: Text(client.email),
                    );
                  },
                );
              } else if (snapshot.hasError) {
                return Center(
                  child: Text(snapshot.error.toString()),
                );
              }
              return Center(
                child: CircularProgressIndicator(),
              );
            },
          },),

    let me know if this is working for you.

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  2. 0

    Say you are getting List of Client Object and Class looks like this

    class Client {
  int id;
  String name;
  String mail;

  Client({required this.id, required this.name, required this.mail});
}

    Now if your question is how can i differentiate some Client from the list and have a separate Grid widget for them?

    If yes, lets take example with above given class
    We have Client with category, Design, Development etc.

    We can simply have a another variable in class such as

    class Client {
  int id;
  String name;
  String mail;
  //type variable to differentiate , could be String or enum if you know exactly 
  String type;
  Client({required this.id, required this.name, required this.mail});
}

    and

    GridView.builder(  
              itemCount: images.length,  
              gridDelegate: SliverGridDelegateWithFixedCrossAxisCount(  
                  crossAxisCount: 2,  
                  crossAxisSpacing: 4.0,  
                  mainAxisSpacing: 4.0  
              ),  
              itemBuilder: (BuildContext context, int index){  

                Client item = Clients[index]; 
                if(item.type == 'Design')
                {
                    // display designClient item
                    return DesignGrid();
                }
                  if(item.type == 'Development')
                {
                    // display developmentType item
                    return DevelopmentGrid();
                }
              }
            )
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