Question 79910 in Flutter Question posted in
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I want to extract only the numbers in this part of the URL.[Regular expressions] – Flutter

I want to extract this part. But I couldn’t do it well. So I need you to tell me how to do it.

Example)
https://twitter.com/straw_berry0721/status/1596714080345415681?s=20&t=1nIbnSZ2YN2m5KZaOjO5GA

1596714080345415681

https://twitter.com/xxx/status/1595920708323999744

1595920708323999744

・my code (failed)

final result = _controller.text;

t = s.lastIndexOf('status'));
s.substring(t)
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2

Answers


  1. 0

    One way to get this is parse it to Uri and use its path like this:

    var str =
    "https://twitter.com/straw_berry0721/status/1596714080345415681?s=20&t=1nIbnSZ2YN2m5KZaOjO5GA";
Uri uri = Uri.parse(str);

print("id= ${uri.path.substring(uri.path.lastIndexOf('/') + 1)}");//id= 1596714080345415681

    or as @MendelG mentions in comment you can go with regex like this:

    var reg = RegExp(r'status/(d+)');
var result = reg.firstMatch(str)?.group(1);
print("result = $result"); // result = 1596714080345415681
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  2. 0

    You could simply extract the last shown number from URLs like https://twitter.com/xxx/status/1595920708323999744 by splitting it to a List<String> then take the last element of it, like this:

    String extractLastNumber(String url) {
return url.split("/").last;
}


final extractedNumber = extractLastNumber("https://twitter.com/xxx/status/1595920708323999744");

print(extractedNumber); // "1595920708323999744"
print("status: $extractedNumber"); // "status: 1595920708323999744"

    Note: this will return the number as String, if you want to get it as an int number you could use the int.tryParse() method like this:

    print(int.tryParse(extractedNumber)); // 1595920708323999744
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