Question 79770 in Flutter Question posted in
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The element type 'Future<void>' can't be assigned to the list type 'Widget' – Flutter

builder: (context, state) {
          if(state.status == RecievingState.success && state.userData != null){
            return  Column(
            children: [  Vibration.vibrate(); //error
            ],)
            },
            }

as soon as the data is changed from API. I want the phone to vibrate within same page…

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2

Answers


  1. 0

    Column children should be widget only like this

    Column(
children: <Widget>[
const Text('hello'),
const Text('world'),
] )

    if you want to use vibrate please refer

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  2. 0

    If you like vibrate every time the if condition get satisfied, you can do :

    builder: (context, state) {
     if(state.status == RecievingState.success && state.userData != null){
        Vibration.vibrate();
        return  Column(
          children: [

    You can add another bool to control the vibrate on the build method.

    If you like to check the state, Use FutureBuilder.

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