Question 336775 in Html Question posted in
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Html – Javascript group elements with identical classnames

I want to select all elements with class name find-me and group them in separate arrays (or NodeLists) based on their other classes, if idential. Here is an example:

<div class="find-me one two">
  Element 1
</div>
<div class="find-me one two">
  Element 2
</div>
<div class="find-me one two three">
  Element 3
</div>
<div class="find-me one two three">
  Element 4
</div>
<div class="find-me one two four">
  Element 5
</div>
<div class="find-me one two">
  Element 6
</div>
<div class="one two">
  Element 7
</div>

My goal is to have:

  • One array or NodeList with elements 1, 2 and 6 (find-me, one, two)
  • One array or NodeList with elements 3 and 4 (find-me, one, two, three)
  • One array or NodeList with element 5 (find-me, one, two, four)
  • Element 7 should not be taken into account since it doesn’t have the find-me class

I suppose I have to use document.querySelectorAll('.find-me') to first get a NodeList of all the elements I am interested in.

But then? I was thinking I could compare the list of classes from the current element with the previous one but how can I keep track of what element goes to what group? Any idea how to achieve that?

Tags:

2

Answers


  1. 0

    You can use this code:

    const findMeElements = document.querySelectorAll('.find-me');

const groupedElements = {};

findMeElements.forEach(element => {
    const currentClasses = Array.from(element.classList);
    const otherClasses = currentClasses.filter(className => className !== 'find-me');
    const key = otherClasses.join(',');
    if (groupedElements[key]) {
        groupedElements[key].push(element);
    } else {
        groupedElements[key] = [element];
    }
});

console.log(groupedElements);
    <div class="find-me one two">
  Element 1
</div>
<div class="find-me one two">
  Element 2
</div>
<div class="find-me one two three">
  Element 3
</div>
<div class="find-me one two three">
  Element 4
</div>
<div class="find-me one two four">
  Element 5
</div>
<div class="find-me one two">
  Element 6
</div>
<div class="one two">
  Element 7
</div>
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  2. 0

    You can iterate through each element in the NodeList then for each element, extract its classList and convert it into a string so you can use it as a key in an object. If an array already exists for that particular combination of classes, push the element into that array. If not, create a new array (or NodeList) and add the element to it.

    Demo:

    const elements = document.querySelectorAll('.find-me');
const groupedElements = {};

elements.forEach(element => {
  const classList = Array.from(element.classList).join(' ');
  if (groupedElements[classList]) {
    groupedElements[classList].push(element);
  } else {
    groupedElements[classList] = [element];
  }
});

// Log only the class combinations and the number of elements in each group
for (const classList in groupedElements) {
  console.log(`Classes: ${classList}, Count: ${groupedElements[classList].length}`);
}
    <div class="find-me one two">
  Element 1
</div>
<div class="find-me one two">
  Element 2
</div>
<div class="find-me one two three">
  Element 3
</div>
<div class="find-me one two three">
  Element 4
</div>
<div class="find-me one two four">
  Element 5
</div>
<div class="find-me one two">
  Element 6
</div>
<div class="one two">
  Element 7
</div>
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