Question 69044 in IOS Swift Question posted in
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Convert Date to required format – Ios swift

I need to convert "2022-01-20T00:00:00.000Z" to "dd MMM yyy" format.
I have tried doing it as suggested in a stackoverflow answer but it returns nil

func convertDate(date:String)-> String{
    let dateFormatterGet = DateFormatter()
    dateFormatterGet.dateFormat = "yyyy-MM-dd'T'HH:mm:ssZ"
    let dateFormatterPrint = DateFormatter()
    dateFormatterPrint.dateFormat = "dd MMM yyy"
    if let date = dateFormatterGet.date(from: String(date)) {
        let convertedDate = dateFormatterPrint.string(from: date)
        return convertedDate
    } else {
        print("There was an error decoding the string")
    }
    return "nil"
}
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2

Answers


  1. Chosen as BEST ANSWER
    0

    got the answer

    func convertDate(date:String)-> String{
    let dateFormatterGet = DateFormatter()
    dateFormatterGet.dateFormat =  "yyyy-MM-dd'T'HH:mm:ss.sssZ"
    let dateFormatterPrint = DateFormatter()
    dateFormatterPrint.dateFormat = "dd MMM yyy"
    if let date = dateFormatterGet.date(from: String(date)) {
       let convertedDate = dateFormatterPrint.string(from: date)
       return convertedDate
    } else {
       print("There was an error decoding the string")
    }
   return "nil"
}
 print(convertDate(date: "2022-01-20T00:00:00.000Z"))

  2. 0

    The fractional seconds are missing in the date format string. It’s yyyy-MM-dd'T'HH:mm:ss.SSSZ.

    And you are not using the date parameter. To avoid confusion with the local variable date rename it.

    And you don’t need two date formatters and it’s highly recommended to set the Locale to a fixed value

    func convertDate(dateString: String) -> String {
    let dateFormatter = DateFormatter()
    dateFormatter.locale = Locale(identifier: "en_US_POSIX")
    dateFormatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSSZ"

    if let date = dateFormatter.date(from: dateString) {
       dateFormatter.dateFormat = "dd MMM yyy"
       return dateFormatter.string(from: date)
    } else {
       print("There was an error decoding the string")
       return ""
    }
   
}
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