Question 51762 in Javascript Question posted in
A very good W3school tutorial can be found here.

Arrays output not giving proper result in JS – Javascript

Here, I have created an array that will print the output, but the second output did not give a valid result, like I work as a Web Dev in Ind. I want, but it prints I work as a Sam in 27. So, what do I need to change about this program? 

const arr = [
  (name, age) => {
    console.log(`My name is ${name} and I am ${age} years old.`);
  },
  (job, city) => {
    console.log(`I work as a ${job} in ${city}.`);
  }
];

for (let i = 0; i < arr.length; i++) {
  arr[i]("Sam", 27, "Web Dev", "Ind");
}
Tags:

2

Answers


  1. 0

    You are passing all 4 parameters into each function, which only takes 2 parameters.

    In your code:

    for (let i = 0; i < arr.length; i++) {
  arr[i]("Sam", 27, "Web Dev", "Ind");
}

    Basically what is being run are these two function calls:

    arr[0]("Sam", 27, "Web Dev", "Ind")
arr[1]("Sam", 27, "Web Dev", "Ind")

    Where what you want to run is this:

    arr[0]("Sam", 27)
arr[1]("Web Dev", "Ind")

    So you will have to go about passing your parameters, or executing your functions in a different way.

    Login or Signup to reply.
  2. 0

    To get something like the effect you want, you can use destructuring:

    const arr = [
  ({name, age}) => {
    console.log(`My name is ${name} and I am ${age} years old.`);
  },
  ({job, city}) => {
    console.log(`I work as a ${job} in ${city}.`);
  }
];

for (let i = 0; i < arr.length; i++) {
  arr[i]({ name: "Sam", age: 27, job: "Web Dev", city: "Ind"});
}

    Destructuring allows each function to decide which properties to pluck out of the passed object. You could add another function:

    const arr = [
  ({name, age}) => {
    console.log(`My name is ${name} and I am ${age} years old.`);
  },
  ({job, city}) => {
    console.log(`I work as a ${job} in ${city}.`);
  },
  ({city, age}) => {
    console.log(`At ${age} years old, I find ${city} to be a lot of fun.`);
  }
];

for (let i = 0; i < arr.length; i++) {
  arr[i]({ name: "Sam", age: 27, job: "Web Dev", city: "Ind"});
}
    Login or Signup to reply.
Please signup or login to give your own answer.

Back To Top
Search