Question 162168 in Javascript Question posted in
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Can Javascript run forEach in order of value inside of a loop?

I have a forEach loop that calls a function for each element in the loop. One of the elements is an element called index that has values as such:

"fields": [
                {
                    "label": "ID",
                    "index": 0.0
                },
                {
                    "label": "field 1",
                    "index": 1.0
                },
                {
                    "label": "field 2",
                    "index": 2.0
                },
                {
                    "label": "field 3",
                    "index": 2.7
                }
]

My Code:

const func2 = (result) => {
  result.data.fields.forEach((d) => {
    otherFunc(d.label);
  });
});

const otherFunc = (d) => //do something

As of now otherFunc is being called in any order. Can it be called based on the index field in result from low to high. That is call in the order of ID, field 1, field 2, field 3` instead of a random order.

Tags:

2

Answers


  1. 0

    You can sort the fields array based on the index value before iterating over it:

    ....
result.data.fields
 .sort((a, b) => a.index - b.index) //sort the fields array based on the index
 .forEach((d) => {
   otherFunc(d.label);
 });
....
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  2. 0

    You first need to sort your array :

    try this :

     const func2 = (result) => {
    result.data.fields
  .sort((a, b) => a.index - b.index) // sort by index in ascending order
   .forEach((d) => {
    otherFunc(d.label);
  });
 };

 const otherFunc = (d) => {
   // do something
  };
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