Question 51846 in Javascript Question posted in
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Finding the biggest word – Javascript

Hello I tryed converting a string to array and then finding the biggest word, output should be length of the word in numbers. Im not sure what im doing wrong and why this code is not working if someone could point it out for me I would be very grateful.

function findLongestWordLength(str) {
  let words=str.split(" ");
  let bigword=0;
  
  for(let i=0; i<=words.length; i++) {
      if(words[i].length>bigword) {
          bigword=words[i].length;
      }
  }
  return bigword; 
}
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5

Answers


  1. 0

    In your for loop, you are iterating a bit far away.
    You can replace i<= words.length by i< words.length

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  2. 0

    It’s because your loop runs longer than there is elements in array.

    Change i<=words.length to i<words.length

    function findLongestWordLength(str) {
  let words = str.split(" ");
  let bigword = 0;


  for (let i = 0; i < words.length; i++) {

    if (words[i].length > bigword) {
      bigword = words[i].length;
    }

  }
  
  return bigword;
}

console.log(findLongestWordLength('a aaa bb c'));
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  3. 0

    You can also use Math.max with passed mapped array of words lengths:

    const findLongest = (str) => {
  const words = str.split(' ');
  const longest = Math.max(...words.map(({ length }) => length));
  return longest;
};

const str = 'This is the test string';
const longestLength = findLongest(str);
console.log(longestLength);
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  4. 0 
    function findLongestWordLength(str) {
    let words = str.split(" ");
    let biglength = Math.max(...words.map(({ length }) => length));
    let word = [];
    for (let i = 0; i < words.length; i++) {
        if (words[i].length == biglength) {
            word.push(words[i]);
        }
    }
    return word;
}
console.log(findLongestWordLength('a bb ccc ddd ee f'));
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  5. 0 
    function findBigestWordLength(wordsParams) {
  const words = wordsParams.split(' ');

  console.log(Math.max(...words.map((word) => word.length)));
}

findBigestWordLength('a bb ccc dddd eeeee');
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