Question 52798 in Javascript Question posted in
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How to delete data from one nested array if it matches with the other array ID – Javascript

I need to remove an nested array if it matches the id of the main array.

arrayOne =

[
    {
        "id": "1",
        "role": [
            "pos_cashier_1",
            "pos_manager"
        ]
    },
    {
        "id": "2",
        "role": [
            "pos_manager",
            "pos_cashier_2"
        ]
    }
]

arrayTwo

[
    {
        "label": "Sessions Sandringham",
        "value": "1"
    },
    {
        "label": "Sessions West Brunswick",
        "value": "2"
    },
    {
        "label": "Global",
        "value": null
    }
]

I need to remove the arrays in the arrayTwo if its value == id in the arrayOne.
Can someone help me…

Tags:

4

Answers


  1. 0

    You can first create a Set of all the ids in the first array, then filter the second array based on the existence of the value property in that Set.

    let arr1=[{id:"1",role:["pos_cashier_1","pos_manager"]},{id:"2",role:["pos_manager","pos_cashier_2"]}],arr2=[{label:"Sessions Sandringham",value:"1"},{label:"Sessions West Brunswick",value:"2"},{label:"Global",value:null}];
let ids = new Set(arr1.map(o => o.id));
let res = arr2.filter(x => !ids.has(x.value));
console.log(res);
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  2. 0

    It’s more efficient to create a set of ids first, but you can also do it as a one-liner using find like this:

    const arr1 = [{"id":"1","role":["pos_cashier_1","pos_manager"]},{"id":"2","role":["pos_manager","pos_cashier_2"]}]
const arr2 = [{"label":"Sessions Sandringham","value":"1"},{"label":"Sessions West Brunswick","value":"2"},{"label":"Global","value":null}]

console.log(arr2.filter(({value:v})=>!arr1.some(({id})=>id===v)))
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  3. 0

    You can also do using find and filter

    const arr1 = [{"id":"1","role":["pos_cashier_1","pos_manager"]},{"id":"2","role":["pos_manager","pos_cashier_2"]}]
const arr2 = [{"label":"Sessions Sandringham","value":"1"},{"label":"Sessions West Brunswick","value":"2"},{"label":"Global","value":null}]

let output = arr2.filter(d => d.value == arr1.find(info => info.id == d.value))

console.log(output)
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  4. 0

    You can use filter and some like this:

    const arrayOne = [
  {
    "id": "1",
    "role": [
      "pos_cashier_1",
      "pos_manager"
    ]
  },
  {
    "id": "2",
    "role": [
      "pos_manager",
      "pos_cashier_2"
    ]
  }
];

const arrayTwo = [
  {
    "label": "Sessions Sandringham",
    "value": "1"
  },
  {
    "label": "Sessions West Brunswick",
    "value": "2"
  },
  {
    "label": "Global",
    "value": null
  }
];
const filtered = arrayTwo.filter(({ value }) => !arrayOne.some(({ id }) => id === value));
console.log(filtered)
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