Question 49312 in Javascript Question posted in
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How to detect if an object as at least two properties valued? – Javascript

I have many javascript objects which are like:

{
  "id": "123",
  "name": undefined,
  "other": undefined,
  "and": "so on",
  ... and many others, each time different fields
}

But most of the time the fields can be all undefined except id (which is always != undefined).

I would like a method to detect if an object has AT LEAST ONE valued prop BESIDES "id".

What do you recommend?

Tags:

2

Answers


  1. 0

    you can use Object.entries and some

    const a = {
  "id": "123",
  "name": undefined,
  "other": undefined,
  "and": "so on",  
}

const b = {
  "id": "123",
  "name": undefined,
  "other": "bla",
  "and":  "bla",  
}

const c = {
  "id": "123",
  "name": undefined,
  "other": undefined,
  "and":  undefined,  
}

const hasValue = obj => Object.entries(obj).some(([k,v]) => k!=='id' && v!==undefined)

console.log(hasValue(a))
console.log(hasValue(b))
console.log(hasValue(c))
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  2. 0

    We can use for in loop. In the loop we put condition that key can’t be id and other keys cannot be undefined. For Example :

    function detectTwoValuedProperty(obj) {
  for (let key in obj) {
    if (key !== "id" && obj[key] !== undefined) {
      return true;
    }
  }
  return false;
}

const objectOne = {
  "id": "123",
  "name": undefined,
  "other": undefined,
};

const objectTwo = {
  "id": "456",
  "name": "Fred Hors",
  "age": undefined,
};

console.log(detectTwoValuedProperty(objectOne)); // return false
console.log(detectTwoValuedProperty(objectTwo)); // return true
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